如何使用jquery过滤json数据

Question

这是我的 JSON 数据：

[{"id":"1","rawId":"1","displayName":"user name 1","name":{"familyName":"user","givenName":"name","formatted":"user name 1"},"nickname":null,"phoneNumbers":[{"id":"2","pref":false,"value":"9874563210","type":"other"}],"emails":null,"addresses":null,"ims":null,"organizations":null,"birthday":null,"note":null,"photos":null,"categories":null,"urls":"http://www.user1.com"},{"id":"2","rawId":"1","displayName":"user name 2","name":{"familyName":"user","givenName":"name","formatted":"user name 2"},"nickname":null,"phoneNumbers":[{"id":"2","pref":false,"value":"9632587410","type":"other"}],"emails":null,"addresses":null,"ims":null,"organizations":null,"birthday":null,"note":null,"photos":null,"categories":null,"urls":"http://www.yahoo.com"},{"id":"3","rawId":"1","displayName":"user name 3","name":{"familyName":"user","givenName":"name","formatted":"user name 3"},"nickname":null,"phoneNumbers":[{"id":"2","pref":false,"value":"9858745852","type":"other"}],"emails":null,"addresses":null,"ims":null,"organizations":null,"birthday":null,"note":null,"photos":null,"categories":null,"urls":null},{"id":"4","rawId":"1","displayName":"Distress Number","name":{"familyName":"Number","givenName":"Distress","formatted":"Distress Number"},"nickname":null,"phoneNumbers":[{"id":"2","pref":false,"value":"8547125693","type":"other"}],"emails":null,"addresses":null,"ims":null,"organizations":null,"birthday":null,"note":null,"photos":null,"categories":null,"urls":"http://www.goo.com"}]

javascript function onSuccess(a){for(var e="",l=0;l"+a[l].displayName+":"+a[l].phoneNumber[0].value+"";$("#setdata").html(e)}

我想获取 displayName 和 phoneNumbers 请指导我如何过滤 json 数据

Answer 1

您可以使用 .map() 创建新的对象数组，其中仅包含相关内容。

以下创建了一个新的对象数组 - 仅包含每个用户的 displayName 和电话号码数组。

var data = [{"id":"1","rawId":"1","displayName":"user name 1","name":{"familyName":"user","givenName":"name","formatted":"user name 1"},"nickname":null,"phoneNumbers":[{"id":"2","pref":false,"value":"9874563210","type":"other"}],"emails":null,"addresses":null,"ims":null,"organizations":null,"birthday":null,"note":null,"photos":null,"categories":null,"urls":"http://www.user1.com"},{"id":"2","rawId":"1","displayName":"user name 2","name":{"familyName":"user","givenName":"name","formatted":"user name 2"},"nickname":null,"phoneNumbers":[{"id":"2","pref":false,"value":"9632587410","type":"other"}],"emails":null,"addresses":null,"ims":null,"organizations":null,"birthday":null,"note":null,"photos":null,"categories":null,"urls":"http://www.yahoo.com"},{"id":"3","rawId":"1","displayName":"user name 3","name":{"familyName":"user","givenName":"name","formatted":"user name 3"},"nickname":null,"phoneNumbers":[{"id":"2","pref":false,"value":"9858745852","type":"other"}],"emails":null,"addresses":null,"ims":null,"organizations":null,"birthday":null,"note":null,"photos":null,"categories":null,"urls":null},{"id":"4","rawId":"1","displayName":"Distress Number","name":{"familyName":"Number","givenName":"Distress","formatted":"Distress Number"},"nickname":null,"phoneNumbers":[{"id":"2","pref":false,"value":"8547125693","type":"other"}],"emails":null,"addresses":null,"ims":null,"organizations":null,"birthday":null,"note":null,"photos":null,"categories":null,"urls":"http://www.goo.com"}]


let details = data.map(item => { return {displayName: item.displayName, phoneNumbers: item.phoneNumbers}})

console.log(details)

Answer 2

您好，如果您想要 jquery，您可以使用每个 (http://api.jquery.com/jquery.each/) 将附加一个显示在 div 显示名称 + 第一个电话号码中的工作示例，如果您想显示所有电话号码，您可以分别添加另一个，如果你需要帮助。

let data = [{"id":"1","rawId":"1","displayName":"user name 1","name":{"familyName":"user","givenName":"name","formatted":"user name 1"},"nickname":null,"phoneNumbers":[{"id":"2","pref":false,"value":"9874563210","type":"other"}],"emails":null,"addresses":null,"ims":null,"organizations":null,"birthday":null,"note":null,"photos":null,"categories":null,"urls":"http://www.user1.com"},{"id":"2","rawId":"1","displayName":"user name 2","name":{"familyName":"user","givenName":"name","formatted":"user name 2"},"nickname":null,"phoneNumbers":[{"id":"2","pref":false,"value":"9632587410","type":"other"}],"emails":null,"addresses":null,"ims":null,"organizations":null,"birthday":null,"note":null,"photos":null,"categories":null,"urls":"http://www.yahoo.com"},{"id":"3","rawId":"1","displayName":"user name 3","name":{"familyName":"user","givenName":"name","formatted":"user name 3"},"nickname":null,"phoneNumbers":[{"id":"2","pref":false,"value":"9858745852","type":"other"}],"emails":null,"addresses":null,"ims":null,"organizations":null,"birthday":null,"note":null,"photos":null,"categories":null,"urls":null},{"id":"4","rawId":"1","displayName":"Distress Number","name":{"familyName":"Number","givenName":"Distress","formatted":"Distress Number"},"nickname":null,"phoneNumbers":[{"id":"2","pref":false,"value":"8547125693","type":"other"}],"emails":null,"addresses":null,"ims":null,"organizations":null,"birthday":null,"note":null,"photos":null,"categories":null,"urls":"http://www.goo.com"}];

let content = "";
$.each(data, function(index, value){
	content += value.displayName+" - "+value.phoneNumbers[0].value+"<br>";
});
$('#results').html(content);

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id="results">

</div>