如何使用python过滤json数据

Question

我正在尝试创建一个函数来过滤从 Google Places api 中提取的 json 数据。如果名称包含字符串“Body Shop”并且类型为 ['car_repair', 'point_of_interest', 'establishment']，我希望它返回企业名称和类型值，否则我希望它拒绝结果。到目前为止，这是我的代码。我已经尝试过，似乎无法找到一种方法来存储某些条件以使搜索更容易。

import googlemaps
import pprint
import time
import urllib.request  






API_KEY = 'YOUR_API_KEY'
lat, lng = 40.35003, -111.95206

#define our Client
gmaps = googlemaps.Client(key = API_KEY)
#Define our Search
places_result = gmaps.places_nearby(location= "40.35003,-111.95206", radius= 40000,open_now= False,type= ['car_repair','point_of_interest','establishment'])
#pprint.pprint(places_result['results'])
time.sleep(3)
places_result_2 = gmaps.places_nearby(page_token = 
places_result['next_page_token'])
pprint.pprint(places_result_2['results'])

places_result_2 = gmaps.places_nearby(page_token = 
places_result['next_page_token'])
    
types = place_details['result']['types']
name = place_details['result']['name']
def match(types,name):
  for val in types: 
      'car_repair','point_of_interest','establishment' in val and "Body Shop" in name
print(name,types)

Answer 1

试试这个：

import googlemaps
import pprint
import time
import urllib.request  




API_KEY = 'YOUR_API_KEY'
lat, lng = 40.35003, -111.95206

#define our Client
gmaps = googlemaps.Client(key = API_KEY)
#Define our Search

places_result = gmaps.places_nearby(location= "40.35003,-111.95206", radius= 40000,open_now= False,type= ['car_repair','point_of_interest','establishment'])


#heres how to retrieve the name of the first result
example_of_name = places_result['results'][0]['name']
print(example_of_name)

#gets places name and type for all the results
for place in places_result['results']:
  print("Name of Place:")
  print(place['name'])
  print("Type of the place:")
  print(place['types'], "\n")