Django TypeError get_object_or_404() 至少需要 1 个参数（给定 0）答案

【问题标题】：Django TypeError get_object_or_404() takes at least 1 argument (0 given)Django TypeError get_object_or_404() 至少需要 1 个参数（给定 0）
【发布时间】：2014-10-20 22:49:15
【问题描述】：

我正在写博客并边走边学 django。我正在尝试合并包含 sluglines 和帖子 ID 的网址。

当我点击管理面板中的“现场查看”链接时，我收到以下错误： NoReverseMatch at /admin/r/7/2/ Reverse for 'article' with arguments '(u'test-post-3', '2')' 和关键字参数 '{}' 未找到。尝试了 0 个模式：[]

当我手动输入网址时，我收到此错误： /articles/test-post-3,2/ get_object_or_404() 的 TypeError 至少需要 1 个参数（给定 0）这是我的代码：

views.py：

from django.shortcuts import render, get_object_or_404
from django.http import HttpResponse, HttpResponseRedirect
from django.template import RequestContext, loader
from django.core.urlresolvers import reverse
from django.views import generic
from django.utils import timezone

# Create your views here.

from articles.models import Content

class IndexView(generic.ListView):
    template_name = 'articles/index.html'
    context_object_name = 'latest_articles_list'

    def get_queryset(self):
        return Content.objects.filter(
            published_date__lte=timezone.now()
        ).order_by('-published_date')[:5]

def detail(request, slugline, id):
    article = get_object_or_404(pk=id)
    return render(request, 'articles/detail.html', {'article': article})

urls.py:

from django.conf.urls import patterns, url
from articles import views

urlpatterns = patterns('',
    url(r'^$', views.IndexView.as_view(), name = 'index'),
    #url(r'^(?P<slugline>[-\w\d]+), (?P<pk>\d+)/$', views.DetailView.as_view(), name='detail')
    url(r'^(?P<slugline>[-\w\d]+),(?P<id>\d+)/$', view=views.detail, name='article'),
)

models.py：

from django.db import models
from django.db.models import permalink
from django.utils import timezone
import datetime
# Create your models here.


class Content(models.Model):
    title = models.CharField(max_length=100, unique=True)
    slugline = models.SlugField(max_length=100, unique=True)
    body = models.TextField()
    published_date = models.DateTimeField('date published')

    def __unicode__(self):
        return self.title

    @permalink
    def get_absolute_url(self):
        # return ('article', (), {
            # 'slugline': self.slugline,
            # 'id': self.id,
        # })
        from django.core.urlresolvers import reverse
        return reverse('article', args=[self.slugline, str(self.id)])

    def was_published_recently(self):
        now = timezone.now()
        return now - datetime.timedelta(days=1) <= self.published_date <= now
    was_published_recently.admin_order_field = 'published_date'
    was_published_recently.boolean = True
    was_published_recently.short_description = 'Published recently?'

主 urls.py:

from django.conf.urls import patterns, include, url

from django.contrib import admin
admin.autodiscover()

urlpatterns = patterns('',
    # Examples:
    # url(r'^$', 'the_Bluntist.views.home', name='home'),
    # url(r'^blog/', include('blog.urls')),

    url(r'^articles/', include('articles.urls', namespace="articles")),
    url(r'^admin/', include(admin.site.urls)),
)

【问题讨论】：

标签： python django

【解决方案1】：

你对get_object_or_404的用法不好：

文档字符串：

get_object_or_404(klass, *args, **kwargs)

使用get() 返回一个对象，如果该对象引发Http404 异常不存在。

klass 可能是 Model、Manager 或 QuerySet 对象。其他都通过了参数和关键字参数用于get() 查询。

注意：与get() 一样，如果多个MultipleObjectsReturned 将被提升找到对象。

你可以做如下：

article = get_object_or_404(Article, pk=id)
article = get_object_or_404(Article.objects, pk=id))
article = get_object_or_404(Article.objects.all(), pk=id))
article = get_object_or_404(Article.objects.filter(pk=id))

【讨论】：

【解决方案2】：

article = get_object_or_404(pk=id)

您必须将模型和过滤器传递给调用。 Documentation here.

article = get_object_or_404(klass, pk=id)

【讨论】：