与另一个物体接触时改变物体颜色

Question

我一直在 youtube 上观看此视频--https://www.youtube.com/watch?v=horBQxH0M5A 这会创建一个弹跳的球列表。

我正在尝试更改代码以使一个球为红色，其余为绿色，当红球“接触”一个绿球时，绿球将颜色变为红色。这并不难，但我还想确保当新的红球碰到另一个绿球时，那个绿球也会变成绿色。

我所做的是创建一个红球和一个绿球列表：

import turtle
import random

wn = turtle.Screen()
wn.bgcolor("white")
wn.title("simulator")

wn.tracer(1, 1)
# red ball
rball = turtle.Turtle()
rball.shape("circle")
rball.color("red")
# rball.penup()
rball.speed(1)
x = random.randint(-10, 10)
y = random.randint(-12, 12)
rball.goto(x,y)

# green ball
gballlist = []
for _ in range(5):
    gballlist.append(turtle.Turtle())

for gballpeople in gballlist:
    gballpeople.shape("circle")
    gballpeople.color("green")
    gballpeople.speed(1)
    xh = random.randint(-10, 10)
    yh = random.randint(-12, 12)
    gballpeople.goto(xh, yh)

while True:
    wn.update()
    # rball.dy += acclerate
    rball.dy = random.randint(-2, 2)
    rball.dx = random.randint(-2, 2)
    rball.setx(rball.xcor() + rball.dx)
    rball.sety(rball.ycor() + rball.dy)
    # list = [-1, 1]
    # angel = random.choice(list)
    angel = -1
    if rball.xcor() < -100:
        rball.dx *= angel
    if rball.xcor() > 100:
        rball.dx *= angel
    if rball.ycor() < -100:
        rball.dy *= angel
    if rball.ycor() > 100:
        rball.dy *= angel

    for gball in gballlist:
        gball.dy = random.randint(-2, 2)
        gball.dx = random.randint(-2, 2)
        gball.setx(gball.xcor() + gball.dx)
        gball.sety(gball.ycor() + gball.dy)
        # list = [-1, 1]
        # angel = random.choice(list)
        angel = -1
        if gball.xcor() < -100:
            gball.dx *= angel
        if gball.xcor() > 100:
            gball.dx *= angel
        if gball.ycor() < -100:
            gball.dy *= angel
        if gball.ycor() > 100:
            gball.dy *= angel
# change the color when distance is near
        for gball in gballlist:
            if abs(rball.xcor() - gball.xcor()) < 4 and abs(rball.ycor() - gball.ycor()) < 4 :
                gball.color("red")

有什么建议吗？

Answer 1

以下是我对您的程序的简化，我相信您正在尝试做的事情。当你说：

我还想确保当新的红球碰到另一个 绿球，绿球也会变成绿色。

我猜你的意思是：

... 也会将颜色变为红色。

以下代码不是创建显式列表，而是使用库自己的内部活动海龟列表，并使用海龟的颜色来确定它们碰撞时应该发生什么：

from turtle import Screen, Turtle
from random import randint

screen = Screen()
screen.title("Simulator")
screen.tracer(False)

for uninfected in range(10):
    ball = Turtle()
    ball.shape('circle')
    ball.shapesize(0.5)
    ball.color('green' if uninfected else 'red')
    ball.penup()
    ball.dy = randint(-2, 2)
    ball.dx = randint(-2, 2)
    x = randint(-180, 180)
    y = randint(-180, 180)
    ball.goto(x, y)

while True:
    for ball in screen.turtles():
        x, y = ball.position()

        x += ball.dx
        y += ball.dy

        ball.setposition(x, y)

        if x < -200:
            ball.dx *= -1
        elif x > 200:
            ball.dx *= -1

        if y < -200:
            ball.dy *= -1
        elif y > 200:
            ball.dy *= -1

        # change the color when distance is near

        changed = True

        while changed:
            changed = False

            for other in screen.turtles():
                if ball == other or ball.pencolor() == other.pencolor():
                    continue

                if ball.distance(other) <= 10:
                    ball.color('red')
                    other.color('red')
                    changed = True

    screen.update()

screen.mainloop()  # never reached

Answer 2

您可以从绿色列表中删除绿球并将其附加到红球列表中。然后你必须将红球附加到绿色列表中并将其从红色列表中删除。

Answer 3

将代码的结尾部分更改为：

# change the color when distance is near
        for gball in gballlist:
            if abs(rball.xcor() - gball.xcor()) < 4 and abs(rball.ycor() - gball.ycor()) < 4 :
                if gball.color()[0] != 'red':
                    gball.color("red")
                else:
                    gball.color("green")