物理问题统一 3d

Question

我的统一游戏是弹簧，当您按住空格键时，弹簧会向后移动。当您松开空格键时，弹簧会根据按住空格键时产生的扭矩大小而释放。

当它被释放时，弹簧刚好在球体内重叠，我需要球根据 Power 变量中的功率量更快或更慢地向前移动。

我不能使用 Rigidbody.Addforce，因为弹簧需要使球移动。

脚本注释：

-> 如果弹簧完全伸出（释放），它的值应该是 -2 如果它保持在最大扭矩，它的 x 轴值应该是 -2.2

---

using UnityEngine;
using System.Collections;

public class SpringMechanics : MonoBehaviour {

public bool SpringIn;
public float Power;
public bool SpringReleased;
void Update()
{
    // IF THE SPRINGS X POSITION IS AT -2 OR ABOVE THAT VALUE IT WILL MARK THE SPRING IN VARIBALE AS TRUE

    if (transform.position.x >=-0.5f)
    {
        SpringIn = false;

    }
    else
    {
        SpringIn = true;
    }

    //CHECKS IF MOUSE SPACE BUTTON IS DOWN AND IF SO MOVES SPRING IN

    if (Input.GetKey (KeyCode.Space) && transform.position.x <= 2.3) {
                    Debug.Log ("Spring Being Compressed");

                    // Moves Spring Backwards when space key is down

        //rigidbody.velocity = new Vector3(rigidbody.velocity.x - 0.05f * Time.deltaTime,rigidbody.velocity.y,rigidbody.velocity.z);
                            transform.position = (new Vector3 (transform.position.x - 0.05f * Time.deltaTime, transform.position.y, transform.position.z));
                            // Adds 3 Units Of Power Every Second While Key Is Down
                            Power += 2 * Time.deltaTime;

            }
    //Releases Ball When Space Bar Is Up After Being Down

    if (Input.GetKeyUp (KeyCode.Space))
    {
        SpringReleased = true;
    }

    if (SpringReleased == true) 
    {
        FireBall();

    }
}

//When Firing Ball Executer Below Function
void FireBall()
{
    if (transform.position.x <= -2){
        rigidbody.velocity = new Vector3(rigidbody.velocity.x + Power * Time.deltaTime,rigidbody.velocity.y,rigidbody.velocity.z);
        //transform.position = (new Vector3 (transform.position.x + Power * Time.deltaTime, transform.position.y, transform.position.z));
        transform.position = (new Vector3 (-2, transform.position.y, transform.position.z));

        if (transform.position.x >= -2 && SpringReleased == true){
            SpringReleased=false;
            Power = 0;
            rigidbody.velocity = new Vector3(0,0,0);
            Debug.Log ("Reset Spring");

            }
        }   
    }
}

如何根据功率变量的值使用弹簧将其向右击打？

Answer 1

改为将力施加到弹簧（或弹簧的某些部分，如顶部的单独网格），其余的由物理引擎完成。