python pygame暂停函数

Question

我是初学者，我的代码有问题。在这里您可以看到我的代码的简短摘录。

这是我创建的一个简单的蛇游戏，但我试图添加一个暂停。我知道了，但是当我开始暂停时，我无法关闭它。

我的代码中可能有一个基本错误，所以我无法前进。我希望你能帮助我。

提前谢谢你！

def checkquit(e):
    running = True
    pause = False
    for ev in e:
        if ev.type == pygame.QUIT:
            exit(0)
            running = True

        if ev.type == pygame.KEYDOWN and ev.key == pygame.K_ESCAPE:
            quit(0)
            running = True

        if ev.type == pygame.KEYDOWN and ev.key == pygame.K_p:
            pause = False

    while pause:
        #running = False
        pause = True   
        red = (255,0,0)

        screen = pygame.display.set_mode((800,500))
        screen.fill((0,0,0))

        my_font = pygame.font.SysFont("monospace", 50)
        my_font_two = pygame.font.SysFont("monospace", 10)

        text1 = myfont.render("Pause!", 100, red)
        text2 = myfont.render("Please restart the game", 100, red)

        screen.blit(text2, (10, 200))
        screen.blit(text1, (230, 100))

        pygame.display.update()

        for ev in e:
            if ev.type == pygame.QUIT:
                pause = False
            if ev.type == pygame.KEYDOWN and ev.key == pygame.K_ESCAPE:
                pause = False      
            if ev.type == pygame.KEYDOWN and ev.key == pygame.K_p:
                pause = True

Answer 1

暂停屏幕显示在单独的应用程序循环中。您也必须在该循环中获取事件。请注意，在您的代码中，e 的内容在“暂停”循环中永远不会改变：

def checkquit(e):
    global running
    running = True
    pause = False
    for ev in e:
        if ev.type == pygame.QUIT:
            exit(0)
            running = True
        if ev.type == pygame.KEYDOWN and ev.key == pygame.K_ESCAPE:
            quit(0)
            running = True
        if ev.type == pygame.KEYDOWN and ev.key == pygame.K_p:
            pause = True

    while pause:

        # [...]


        # get the new events
        e = pygame.event.get()

        # handle the events in the loop
        for ev in e:
            if ev.type == pygame.QUIT:
                pause = False
            if ev.type == pygame.KEYDOWN and ev.key == pygame.K_ESCAPE:
                pause = False      
            if ev.type == pygame.KEYDOWN and ev.key == pygame.K_p:
                pause = True

runnung 似乎是全局命名空间中的一个变量。你必须使用global statement 来改变它的状态。 此外，在“暂停”循环中重新创建窗口表面是多余的。

screen = pygame.display.set_mode((800,500))

---

我建议更改游戏流程。使用 1 个应用程序循环。例如：

myfont=pygame.font.SysFont("monospace",50)
myfonttwo=pygame.font.SysFont("monospace",10)
text1=myfont.render("Pause!",100,red)
text2=myfont.render("Please restart the game",100,red)

def checkquit(e):
    global running, pause
    for ev in e:
        if ev.type == pygame.QUIT:
            exit(0)
            running = True
        if ev.type == pygame.KEYDOWN and ev.key == pygame.K_ESCAPE:
            if pause:
                pause = False
            else:
                quit(0)
                running = True
        if ev.type == pygame.KEYDOWN and ev.key == pygame.K_p:
            pause = not pause

running, pause = True, False
while running:
    events = pygame.event.get()
    checkquit(events)

    screen.fill((0,0,0))
    if pause:
        # draw pause screen
        screen.blit(text2,(10,200))
        screen.blit(text1,(230,100))

    else:
        # draw game
        # [...]

    pygame.display.update() 

Answer 2

我将我的代码编辑为这个：

def checkquit(e): 运行=真 暂停 = 假 对于 e 中的 ev： 如果 ev.type == pygame.QUIT： 退出(0) 运行 = 假 暂停 = 假

    if ev.type == pygame.KEYDOWN and ev.key == pygame.K_ESCAPE:
        quit(0)
        running = False
        pause = False

    if ev.type == pygame.KEYDOWN and ev.key == pygame.K_p:
            pause = True
            running = False



while pause: 
    pause = True
    red = (255,0,0)
    screen = pygame.display.set_mode((800,800))
    screen.fill((0,0,0))
    myfont=pygame.font.SysFont("monospace",50)
    myfonttwo=pygame.font.SysFont("monospace",10)
    myfonttwo=pygame.font.SysFont("monospace",10)
    text1=myfont.render("Pause!",100,red)
    text2=myfont.render("Please resume your game!",100,red)
    text3=myfont.render("Game starts in 10 seconds!",100,red)
    screen.blit(text2,(50,200))
    screen.blit(text1,(300,100))
    screen.blit(text3,(0,300))

    pygame.display.update()
    pygame.time.delay(4500)
    if ev.type == pygame.KEYDOWN and ev.key == pygame.K_p:
        pause = False

而且效果很好！感谢您的建议！