【发布时间】:2015-05-18 22:30:57
【问题描述】:
我想编写测试来检查两个对象是否相同。当断言失败时,我想知道哪些字段是相同的,哪些不是。我可以对每个字段进行断言,但想知道是否有办法对对象进行比较。
卡车类:
import java.util.List;
public class Truck {
private String model;
private String make;
private int year;
private List<TruckPartsObject> parts;
public Truck(String model, String make, int year) {
super();
this.model = model;
this.make = make;
this.year = year;
}
public String getModel() {
return model;
}
public void setModel(String model) {
this.model = model;
}
public String getMake() {
return make;
}
public void setMake(String make) {
this.make = make;
}
public int getYear() {
return year;
}
public void setYear(int year) {
this.year = year;
}
public List<TruckPartsObject> getParts() {
return parts;
}
public void setParts(List<TruckPartsObject> parts) {
this.parts = parts;
}
@Override
public String toString() {
return "Truck{" + "model='" + model + '\'' + ", make='" + make + '\''
+ ", year=" + year + ", parts=" + parts + '}';
}
}
TruckPartsObject 类:
import java.util.HashMap;
public class TruckPartsObject {
private String name;
private String price;
private HashMap<String, String> partsHashMap;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getPrice() {
return price;
}
public void setPrice(String price) {
this.price = price;
}
public HashMap<String, String> getPartsHashMap() {
return partsHashMap;
}
public void setPartsHashMap(HashMap<String, String> partsHashMap) {
this.partsHashMap = partsHashMap;
}
@Override
public String toString() {
return "TruckPartsObject{" + "name='" + name + '\'' + ", price='"
+ price + '\'' + ", partsHashMap=" + partsHashMap + '}';
}
}
测试:
@Test
public void truckTest () {
Truck pickupTruck1 = new Truck("Big 10", "Chevy", 1976);
Truck pickupTruck2 = new Truck("Big 10", "Chevy", 1976);
List<TruckPartsObject> parts1 = new ArrayList<TruckPartsObject>();
TruckPartsObject truckPartsObject1 = new TruckPartsObject();
truckPartsObject1.setName("part1");
parts1.add(truckPartsObject1);
pickupTruck1.setParts(parts1);
List<TruckPartsObject> parts2 = new ArrayList<TruckPartsObject>();
TruckPartsObject truckPartsObject2 = new TruckPartsObject();
truckPartsObject2.setName("part1");
parts2.add(truckPartsObject2);
pickupTruck2.setParts(parts2);
pickupTruck2.setParts(parts2);
System.out.println(pickupTruck1);
System.out.println(pickupTruck2);
//how to assert pickupTruck1 and pickupTruck2 have the same
}
如何断言pickupTruck1和pickupTruck2相同?
【问题讨论】:
-
Truck对象是不是故意没有equals方法,还是只是这里没有显示? -
它没有equals方法。如果这是正确的解决方案,我可以添加 equals 方法。如果我这样做,那么我还必须覆盖 hasCode() 并添加逻辑以检查值是否不为空并手动检查每个值。此外,当测试失败时,显示实际与预期的错误消息将不那么清楚。所以想知道有没有更好的解决方案。
-
可以使用 Apache commons-lang3 库的 EqualsBuilder、HashCodeBuilder 和 ToStringBuilder。这将在失败时提供有用的错误消息。
标签: testing assert assertions hamcrest rest-assured