【发布时间】:2023-03-16 05:32:02
【问题描述】:
我决定将那个 Squarey 游戏移到 pygame,现在我有 2 个可以移动并撞到墙壁的矩形。但是,矩形可以相互移动。我怎样才能让他们撞到对方并停下来? 我的代码:
import pygame
pygame.init()
screen = pygame.display.set_mode((1000, 800))
pygame.display.set_caption("Squarey")
done = False
is_red = True
x = 30
y = 30
x2 = 100
y2 = 30
clock = pygame.time.Clock()
while not done:
for event in pygame.event.get():
if event.type == pygame.QUIT:
done = True
if event.type == pygame.KEYDOWN and event.key == pygame.K_SPACE:
is_red = not is_red
pressed = pygame.key.get_pressed()
if pressed[pygame.K_UP]: y -= 3
if pressed[pygame.K_DOWN]: y += 3
if pressed[pygame.K_LEFT]: x -= 3
if pressed[pygame.K_RIGHT]: x += 3
if pressed[pygame.K_w]: y2 -= 3
if pressed[pygame.K_s]: y2 += 3
if pressed[pygame.K_a]: x2 -= 3
if pressed[pygame.K_d]: x2 += 3
if y < 0:
y += 3
if x > 943:
x -= 3
if y > 743:
y -= 3
if x < 0:
x += 3
if y2 < 0:
y2 += 3
if x2 > 943:
x2 -= 3
if y2 > 743:
y2 -= 3
if x2 < 0:
x2 += 3
screen.fill((0, 0, 0))
if is_red: color = (252, 117, 80)
else: color = (168, 3, 253)
if is_red: color2 = (0, 175, 0)
else: color2 = (255, 255, 0)
rect1 = pygame.draw.rect(screen, color, pygame.Rect(x, y, 60, 60))
rect2 = pygame.draw.rect(screen, color2, pygame.Rect(x2, y2, 60, 60))
pygame.display.flip()
clock.tick(60)
pygame.quit()
【问题讨论】:
标签: python pygame collision rectangles