内部连接两个表时出现语法错误

Question

我正在尝试加入表 events 和 venues，但是在内部加入时遇到了问题。我就是这样做的：

$query =    "SELECT e.*, v.* FROM events e WHERE start_datetime >= '$DATE_START_SELECTED' AND end_datetime < '$DATE_END_SELECTED'".
           "INNER JOIN venues v ON e.VENUE_LOCATION = v.VENUE_ID";

由于某种原因，我遇到了这样的错误：

您的 SQL 语法有错误；检查手册 对应于您的 MySQL 服务器版本，以便使用正确的语法 在第 1 行的“INNER JOIN 场地 v ON e.VENUE_LOCATION = v.VENUE_ID”附近

知道为什么吗？谢谢！

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编辑：

我将代码更新为如下所示：

$query =    "SELECT e.*, v.* FROM events e ".
        "INNER JOIN venues v ON e.VENUE_LOCATION = v.VENUE_ID".
        "WHERE start_datetime >= '$DATE_START_SELECTED' AND end_datetime < '$DATE_END_SELECTED'";

只得到这个错误：

您的 SQL 语法有错误；检查手册 对应于您的 MySQL 服务器版本，以便使用正确的语法 'start_datetime > = '2012-03-15 06:00:00' AND end_datetime

Answer 1

您的INNER JOIN 需要位于WHERE 子句之前。

例如，

select e.*, v.*
from events e
inner join venues v on e.VENUE_LOCATION = v.VENUE_ID
where start_datetime >= '$DATE_START_SELECTED' 
    and end_datetime < '$DATE_END_SELECTED'

Answer 2

联接总是在from 之后和where 之前。因此，您的查询将更像以下内容：

SELECT e.*, v.* 
FROM events e 
    INNER JOIN venues v ON e.VENUE_LOCATION = v.VENUE_ID
WHERE start_datetime >= '$DATE_START_SELECTED' 
    AND end_datetime < '$DATE_END_SELECTED'

Answer 3

在最后写下 where 子句（我还将简写符号扩展为“FROM events e to FROM events AS e:

SELECT e.*, v.* FROM events AS e 
INNER JOIN venues AS v ON e.VENUE_LOCATION = v.VENUE_ID
WHERE e.start_datetime >= yourVar AND e.end_datetime < yourOtherVar;