如何枚举单词的组合？

Question

给定带有斜线 definitive/deterministic arithmetic/calculation 的文本，目标是枚举单词的可能组合，例如预期输出：

definitive arithmetic
deterministic arithmetic
definitive calculation
deterministic calculation

另一个例子，输入voice/speech wave information processing method/technique，预期输出：

voice wave information processing method
voice wave information processing technique
speech wave information processing method
speech wave information processing technique

有时会有括号，预期的输出将是枚举输出有和没有括号内的术语，例如输入bactericidal/microbidical (nature/properties)，预期输出：

bactericidal
microbidical
bactericidal nature
bactericidal properties
microbidical nature
microbidical properties

我试过这个用单斜线解决文本，但它太hacky了，有没有更简单的方法？

for english in inputs:
    if sum([1 for tok in english.split(' ') if '/' in tok]) == 1:
        x = [1 if '/' in tok else 0 for tok in english.split(' ') ]

        left = english.split(' ')[:x.index(1)]
        word = english.split(' ')[x.index(1)].split('/')
        right = english.split(' ')[x.index(1)+1:]

        for tok in word:
            print(' '.join([left + [tok] + right][0]))

我如何也捕获多个斜线的情况？

以下是可能的输入列表：

definitive/deterministic arithmetic/calculation
random/stochastic arithmetic/calculation
both ends/edges/terminals
to draw/attract/receive attention
strict/rigorous/exact solution
both ends/edges/terminals
easy to conduct/perform/carry out
easy to conduct/perform/carry out
between/among (equals/fellows)
reference/standard/nominal value
one kind/type/variety/species
primary cause/source/origin
to be disordered/disturbed/chaotic
same category/class/rank
while keeping/preserving/maintaining/holding
driving/operating in the reverse/opposite direction
only/just that portion/much
cannot doubt/question/suspect
does not reach/attain/match
tube/pipe/duct axis
recatangular/Cartesian/orthogonal coordinates
tube/pipe/duct wall
acoustic duct/conduit/channel
site of damage/failure/fault
voice/speech wave information processing method/technique
fundamental/basic theorem/proposition
single/individual item/product
one body/unit/entity
first stage/grade/step
time/era of great leaps/strides
one form/shape/figure
reserve/spare circuit/line
basic/base/backing material
set/collection/group of tables
in the form of a thin sheet/laminate/veneer
minute/microscopic pore/gap
forming/molding and working/machining
small amount/quantity/dose
liquid crystal form/state/shape
to rub/grind/chafe the surface
the phenomenon of fracture/failure/collapse
compound/composite/combined effect
molecular form/shape/structure
…st/…nd/….rd/…th group (periodic table)
the architectural/construction world/realm
to seal/consolidate a material by firing/baking
large block/clump/clod
bruned/baked/fired brick
unbruned/unbaked/unfired brick
kiln/furnance/oven surface
stationary/stator vane/blade
moving/rotor vane/blade
industrial kiln/furnance/oven
mean/average pore size/diameter
hardened/cured/set material
kiln/oven/furnance lining
piping (layout/arrangement/system)
metallic luster/brilliance/shine
mechanical treatment/working/processing
thin-sheet/laminate/veneer manufacture
thin sheet/laminate/veneer
vehicle (cars/trucks/trains) field
sheet/panel/plate thickness
corrosion prevention/resistance/protection
wriggling/squirming/slithering motion
method for forming/molding/shaping
object to be molded/formed/shaped
pressurized molding/forming/shaping equipment
premolded/preformed object/body
to seal/consolidate a material by firing/baking
furnance/kiln/oven wall
slipping/sliding/gliding mode
bactericidal/microbidical (nature/properties)
secondary/rechargeable cell/battery
new region/domain/area

Answer 1

看来您应该只使用itertools.product()。您可以拆分空格和'/'，这将适用于单个单词和组。例如：

from itertools import product

s = "definitive/deterministic arithmetic/calculation"
l = [g.split('/') for g in s.split(' ')]
[" ".join(words) for words in product(*l)]

结果：

['definitive arithmetic',
 'definitive calculation',
 'deterministic arithmetic',
 'deterministic calculation']

或：

s = "voice/speech wave information processing method/technique"
l = [g.split('/') for g in s.split(' ')]
[" ".join(words) for words in product(*l)]

结果：

['voice wave information processing method',
 'voice wave information processing technique',
 'speech wave information processing method',
 'speech wave information processing technique']

Answer 2

这将尊重输入中的括号。这个想法是在开头用/替换括号(...)，所以(string1/string2)会变成/string1/string2。然后split('/') 将创建包含空字符串['', 'string1', 'string2'] 的列表。然后你将使用itertools.product:

data = [
    'definitive/deterministic arithmetic/calculation',
    'vehicle (cars/trucks/trains) field',
]

import re
from itertools import product

for d in data:
    l = [w.split('/') for w in re.sub(r'\(([^)]+)\)', r'/\1', d).split()]
    print([' '.join(i for i in p if i) for p in product(*l)])

打印：

['definitive arithmetic', 'definitive calculation', 'deterministic arithmetic', 'deterministic calculation']
['vehicle field', 'vehicle cars field', 'vehicle trucks field', 'vehicle trains field']

Answer 3

根据您的问题，这里有一个正则表达式，可用于根据需要解析您的输入

\w+/\w+|\W+\w+|\W+\w+\W+

使用这个正则表达式，你可以得到你需要的所有单词。在这个正则表达式中，我们放置可选条件来检查字符串是否有可选字符（如（）或其他一些字符）

您可以使用 re.findall() 方法以文本字符串为例来解析上述正则表达式

import re

expression="\w+\/\w+|\W+\w+|\W+\w+\W+"

test_string="abcd/efgh(sabdhaksdaksdas)/ijkl/mnop1/qerst/(abcdef)"

print(re.findall(expression,test_string))

此正则表达式可能存在一些问题。您可以以此为起点。

在此之后，您可以使用以下答案中的 itertools.product 方法来获取所有可能的单词组合。