Shell 脚本 - Shell 变量未结转值答案

【问题标题】：Shell Scripting - Shell Variable not carrying forward valueShell 脚本 - Shell 变量未结转值
【发布时间】：2021-05-24 21:24:41
【问题描述】：

#!/bin/bash

while true
do
 if [[ $# -eq 0 ]] ; then

    result=$((operand1+operand2))
    result=$((operand1-operand2))
    result=$((operand1*operand2))

     if [[ $result ]] ; then 
        operand1=$result 
        echo "operand 1 is: $result" 
        echo "" 
     else 
        echo Enter operand1 value: 
        read operand1 

     fi

     # Offer choices
     echo 1. Addition
     echo 2. Subtraction
     echo 3. Multiplication
     echo 4. Division
     echo 5. Exit


     echo Enter your choice:
     read choice


     if [[ $choice != 1 && $choice != 2 && $choice != 3 && $choice != 4 && $choice != 5 ]] ; then
         echo Sorry not a valid operator - please try again 
         echo Enter your choice:
         read choice

     fi

     echo Enter operand2 value:
     read operand2

     # get operands and start computing based on the user's choice
     if [[ $choice -eq 1 ]] ; then

         echo ----------------------------------------
         echo Addition of $operand1 and $operand2 is $((operand1+operand2))
         echo ----------------------------------------
         echo

     elif [[ $choice -eq 2 ]] ; then

         echo ----------------------------------------
         echo Subtraction of $operand1 and $operand2 is $((operand1-operand2))
         echo ----------------------------------------
         echo
     elif [[ $choice -eq 3 ]] ; then

         echo ----------------------------------------
         echo Multiplication of $operand1 and $operand2 is $((operand1*operand2))
         echo ----------------------------------------
         echo
     elif [[ $choice -eq 4 && operand2 -eq 0 ]] ; then
         echo Can not divide by 0 please try again 
         echo Please enter operand2
         read operand2
         echo ----------------------------------------
         echo Division of $operand1 and $operand2 is $((operand1/operand2))
         echo ----------------------------------------
         echo

      elif [[ $choice -eq 4 && operand2 -ne 0 ]] ; then
         echo ----------------------------------------
         echo Division of $operand1 and $operand2 is $((operand1/operand2))
         echo ----------------------------------------
         echo

     elif [[ $choice -eq 5 ]] ; then
         exit

     else
         echo ----------------------------------------
         echo Invalid choice.. Please try again
         echo ----------------------------------------
         echo
     fi

   else
         echo ----------------------------------------
         echo You either passed too many parameters or too less
         echo than the optimum requirement.
         echo
         echo This program accepts a maximum of 2 arguments or no
         echo argument at all in order to run successfully.
         echo ----------------------------------------
   fi
done

我正在专门研究这段代码的顶部。我正在尝试使用它，以便用户的结果将用于下一个操作数 1。每次计算后我得到操作数 1 = 0。知道如何解决这个问题吗？操作数 1 是：0

1. Addition
2. Subtraction
3. Multiplication
4. Division
5. Exit
Enter your choice:
1
Enter operand2 value:
1
----------------------------------------
Addition of 0 and 1 is 1
----------------------------------------

operand 1 is: 0

1. Addition
2. Subtraction
3. Multiplication
4. Division
5. Exit
Enter your choice:

【问题讨论】：

你试过用 bash -x 运行代码吗？
您能否编辑您的问题以显示显示错误的示例运行？
@MarkPlotnick，奇怪的是，当我清除并在我的 shell 中重新输入代码时它可以工作，然后计算我清除之前的所有先前值并添加它们，尽管当我开始时这是我的操作数 1做。添加到问题
循环体开头的result 的3 个赋值的目的是什么？没有分配给 result 取决于所选操作。
您能解释一下if [[ $result ]] 的用途吗？我认为可能有更好的方法。

标签： shell unix scripting

【解决方案1】：

这是一种减少重复代码的方法。注意使用select 来显示菜单。

#!/bin/bash

PS3="Enter the operation: "     # for the select statement

operand() {
    read -r -p "Enter operand${1} value: "
    echo "$REPLY"
}

operand1=$(operand 1)

while true; do
    select operation in Addition Subtraction Multiplication Division Exit; do
        case $operation in
            Exit) exit ;;
            Addition)       op="+"; break ;;
            Subtraction)    op="-"; break ;;
            Multiplication) op="*"; break ;;
            Division)       op="/"; break ;;
        esac
    done

    while true; do
        operand2=$(operand 2)
        if [[ $operation == "Division" ]] && (( operand2 == 0 )); then
            echo Can not divide by 0 please try again 
        else
            break
        fi
    done

    (( result = operand1 $op operand2 ))

    echo "----------------------------------------"
    echo "$operation of $operand1 and $operand2 is $result"
    echo "----------------------------------------"

    echo "operand 1 is: $result" 
    operand1=$result
done

【讨论】：

【解决方案2】：

#!/bin/bash

while true
do

         if [[ $result ]] ; then 

            echo "operand 1 is: $result" 
            echo "" 

         else 
            echo Enter operand1 value: 
            read operand1 

         fi

         # Offer choices
         echo 1. Addition
         echo 2. Subtraction
         echo 3. Multiplication
         echo 4. Division
         echo 5. Exit

 
         echo Enter your choice:
         read choice


         if [[ $choice != 1 && $choice != 2 && $choice != 3 && $choice != 4 && $choice != 5 ]] ; then
             echo Sorry not a valid operator - please try again 
             echo Enter your choice:
             read choice

         fi
 
         echo Enter operand2 value:
         read operand2
 
         # get operands and start computing based on the user's choice
         if [[ $choice -eq 1 ]] ; then
 
             echo ----------------------------------------
             echo Addition of $operand1 and $operand2 is $((operand1+operand2))
             result=$((operand1+operand2))
             echo ----------------------------------------
             echo

         elif [[ $choice -eq 2 ]] ; then
 
             echo ----------------------------------------
             echo Subtraction of $operand1 and $operand2 is $((operand1-operand2))
             result=$((operand1-operand2))
             echo ----------------------------------------
             echo
         elif [[ $choice -eq 3 ]] ; then
 
             echo ----------------------------------------
             echo Multiplication of $operand1 and $operand2 is $((operand1*operand2))
             result=$((operand1*operand2))
             echo ----------------------------------------
             echo
         elif [[ $choice -eq 4 && operand2 -eq 0 ]] ; then
             echo Can not divide by 0 please try again 
             echo Please enter operand2
             read operand2
             echo ----------------------------------------
             echo Division of $operand1 and $operand2 is $((operand1/operand2))
             echo ----------------------------------------
             echo

          elif [[ $choice -eq 4 && operand2 -ne 0 ]] ; then
             echo ----------------------------------------
             echo Division of $operand1 and $operand2 is $((operand1/operand2))
             result=$((operand1/operand2))
             echo ----------------------------------------
             echo

         elif [[ $choice -eq 5 ]] ; then
             exit

         else
             echo ----------------------------------------
             echo Invalid choice.. Please try again
             echo ----------------------------------------
             echo
         fi
done

【讨论】：

你说 "operand 1 is: $result" 但你没有分配operand1结果值。