从多个表中查询数据

Question

好的。我认为我已经引用了THIS 其他与我的情况类似的问题。但我会添加我的情况以及到目前为止我已经尝试过的内容。

Ticket Table    
*-------------------------------*
|t_id | repair_id | customer_id |
| 1   |     10    |     11      | 
| 2   |   11,12   |     12      | 
| 3   |   13,14   |     13      |
| 4   |   15,16   |     14      |
*-------------------------------* 
Repair Table    
*-----------------------------------------------------*
|repair_id  | ticket_id | device_type | repair_status | 
|     10    |    1      |   laptop    |     open      |
|     11    |    2      |   tablet    |     open      |
|     12    |    2      |   phone     |     open      | 
|     13    |    3      |   phone     |     open      |
|     14    |    3      |   tablet    |     open      |
|     15    |    4      |   laptop    |     open      |
|     16    |    4      |   laptop    |     open      |
*-----------------------------------------------------*
Customer Table    
*-----------------------------*
|customer_id | f_name | l_name | 
|     11     |  John  | Hughes |  
|     12     |  Julia | Brown  |   
|     13     |  Tim   | Duncan |  
|     14     |  Tony  | Price  |  
*-----------------------------*

我希望结果表看起来像这样：

Results Table    
*----------------------------------------------------------*
|customer_name | Repair_# | device_type    | repair_status |
| John Hughes  |   10     | laptop         |    open       | 
| Julia Brown  |   11,12  | tablet,phone   |    open       | 
| Tim Duncan   |   13,14  | phone, tablet  |    open       | 
| Tony Price   |   15,16  | laptop, laptop |    open       | 
*----------------------------------------------------------* 

这是我尝试过的查询：

$query  = "SELECT customers.id, customers.f_name, customers.l_name, device_repairs.repair_id, device_repairs.ticket_id, ";
$query .= "device_repairs.device_type,device_repairs.repair_type, device_repairs.ticket_status, ";
$query .= "FROM tickets ";
$query .= "LEFT JOIN customers ON tickets.customer_id = customers.id ORDER BY device_repairs.ticket_id DESC";

我知道我的查询不正确，但我不太确定如何设置 INNER JOIN。

修订版

所以经过一些审查。我添加了一个修改后的表格结构。

Ticket Table    
*--------------------------------------------------------------------*
|t_id|repair_id|cust_id|cust_fname|cust_lname|device_type|repair_stat|
| 1  |   10    |  11   |  John    | Hughes   | Laptop    |   open    |
| 2  |   11    |  12   |  Julia   | Brown    | Tablet    |   open    |
| 2  |   12    |  12   |  Julia   | Brown    | Phone     |   open    | 
*--------------------------------------------------------------------* 
Repair Table    
*-----------------------------------------------------*
|repair_id  | ticket_id | device_type | repair_status | 
|     10    |    1      |   laptop    |     open      |
|     11    |    2      |   tablet    |     open      |
|     12    |    2      |   phone     |     open      | 
|     13    |    3      |   phone     |     open      |
|     14    |    3      |   tablet    |     open      |
|     15    |    4      |   laptop    |     open      |
|     16    |    4      |   laptop    |     open      |
*-----------------------------------------------------*
Customer Table    
*-----------------------------*
|customer_id | f_name | l_name | 
|     11     |  John  | Hughes |  
|     12     |  Julia | Brown  |   
|     13     |  Tim   | Duncan |  
|     14     |  Tony  | Price  |  
*-----------------------------*

修改后的结果表如下：

Results Table    
*----------------------------------------------------------*
|customer_name | Repair_# | device_type    | repair_status |
| John Hughes  |   10     | laptop         |    open       | 
| Julia Brown  |   11     | tablet         |    open       |
| Julia Brown  |   12  |  | phone          |    open       |  
*----------------------------------------------------------* 

希望这会有所帮助并且更有意义。

我创建了这个查询，以便正确输出结果表。感谢您的所有意见。

$sql = "SELECT customers.id, customers.f_name, customers.l_name, device_repairs.repair_id, device_repairs.device_type, ";
$sql .="device_repairs.repair_type, device_repairs.ticket_status, device_repairs.ticketopen ";
$sql .="FROM customers, device_repairs WHERE customers.id = device_repairs.customer_id ORDER BY device_repairs.ticketopen DESC";

Answer 1

票务表设计不佳。我不会将两个维修 ID 放在一个字段中。拥有 ID（主键）和外键的整个想法都丢失了。

您的工单表应该有 7 行而不是 4 行，并且其中的修复 ID 应该只有一个值。此外，repair_id 应该被描述为外键并链接到修复表。

在此之后，您可以在 customer_id 上将客户表连接到工单表，并在工单表上进一步连接维修表。