您需要只传递数组的元素,还是特定的索引->元素映射?我问的原因是您提供的示例数组的索引为 1-6,但默认情况下,bash 数组的索引为 0-5。我将假设索引并不重要(除了顺序);如果需要通过,事情会变得有点复杂。
有两种相当标准的方法可以做到这一点;您可以将两个固定参数作为前两个位置参数($1 和 $2)传递,并将数组作为第三个传递,如下所示:
#!/bin/bash
# Usage example:
# ./scriptname "mylogfolder" "myname" "1 MyScript1" \
# "2 MyScript2 MyScript3 MyScript4 MyScript5 MyScript6 MyScript7 MyScript8 MyScript9 MyScript10 MyScript11" \
# "2 MyScript12 MyScript13" ...
logfolder=$1
processname=$2
script=("${@:3}")
或者,如果这两个值是可选的,您可以将它们设为带参数的选项,如下所示:
#!/bin/bash
# Usage example:
# ./scriptname -l "mylogfolder" -p "myname" "1 MyScript1" \
# "2 MyScript2 MyScript3 MyScript4 MyScript5 MyScript6 MyScript7 MyScript8 MyScript9 MyScript10 MyScript11" \
# "2 MyScript12 MyScript13" ...
while getopts "l:p:" o; do
case "${o}" in
l)
logfolder =${OPTARG} ;;
p)
processname =${OPTARG} ;;
*)
echo "Usage: $0 [-l logfolder] [-p processname] script [script...]" >&2
exit 1
;;
esac
done
shift $((OPTIND-1))
script=("${@}")
在任何一种情况下,要传递一个数组,您都需要使用 "${arrayname[@]}" 将每个元素作为单独的参数传递给脚本。
[编辑] 传递数组索引 with 元素更复杂,因为 arg 列表基本上只是一个字符串列表。您需要以某种方式对索引和元素进行编码,然后在脚本中将它们解析出来。这是一种方法,对数组中的每个事物使用index=element:
#!/bin/bash
# Usage example:
# ./scriptname "mylogfolder" "myname" "1=1 MyScript1" \
# "2=2 MyScript2 MyScript3 MyScript4 MyScript5 MyScript6 MyScript7 MyScript8 MyScript9 MyScript10 MyScript11" \
# "3=2 MyScript12 MyScript13" ...
logfolder=$1
processname=$2
# Parse arguments 3 on as index=element pairs:
declare -a script=()
for scriptarg in "${@:3}"; do
index=${scriptarg%%=*}
if [[ "$index" = "$scriptarg" || -z "$index" || "$index" = *[^0-9]* ]]; then
echo "$0: invalid script array index in '$scriptarg'" >&2
exit 1
fi
script[$index]=${scriptarg#*=}
done
要调用它,您需要以适当的格式打包脚本数组,如下所示:
# Convert the normal script array to a version that has "index=" prefixes
scriptargs=()
for index in "${!script[@]}"; do # iterate over the array _indexes_
scriptargs+=("${index}=${script[$index]}")
done
./script.sh "$logfolder" "$processname" "${scriptargs[@]}"