如何获取每年的积分名称和最大值？ (SQL) [重复]答案

【问题标题】：How to get the name and maximum values of points for each year? (SQL) [duplicate]如何获取每年的积分名称和最大值？ (SQL) [重复]
【发布时间】：2021-11-13 07:59:16
【问题描述】：

这是我目前的代码，它在 T-SQL 中。

我无法添加 driver_name 列。我应该使用什么样的聚合？

SELECT MAX(race_points) max_points, year, driver_name
FROM 

    (SELECT

        CONCAT(forename,' ',surname) AS driver_name,
        year,
        (CONVERT(FLOAT,points)) AS race_points     
     
    FROM 
            results AS r

            INNER JOIN constructors AS c
            ON r.constructorId = c.constructorId

            INNER JOIN drivers AS d
            ON r.driverId = d.driverId

            INNER JOIN races AS rc
            ON r.raceId = rc.raceId) AS sub
GROUP BY year;

这就是 sub 的样子

driver_name	year	race_points
a	2010	2
a	2011	3
b	2011	4
b	2012	3
c	2012	4

我试图让它看起来像谎言

driver_name	year	max_points
a	2010	2
b	2011	4
c	2012	4

任何帮助将不胜感激。

【问题讨论】：

标签： sql sql-server group-by aggregate-functions

【解决方案1】：

使用row_number()，您可以根据您对数字进行分区的方式为您的行编号。如果您对它进行相应的排序，您可以从每个组中选择第 1 行。

WITH cte as
(
   SELECT
     CONCAT(forename,' ',surname) AS driver_name,
     year,
     (CONVERT(FLOAT,points)) AS race_points,
     row_number() over (partition by year order by (CONVERT(FLOAT,points)) desc) as rn     
   FROM 
     results AS r    
     INNER JOIN constructors AS c ON r.constructorId = c.constructorId
     INNER JOIN drivers AS d ON r.driverId = d.driverId
     INNER JOIN races AS rc ON r.raceId = rc.raceId
)
SELECT * FROM cte 
WHERE rn = 1

【讨论】：