如何获取每年的积分名称和最大总和值？答案

【问题标题】：How to get the name and maximum sum values of points for each year?如何获取每年的积分名称和最大总和值？
【发布时间】：2021-11-15 00:48:17
【问题描述】：

到目前为止，这是我的代码。它在 T-SQL 中。

但是，它只选择每年具有最大值的项目，而不是总分。

WITH cte as
(
   SELECT
     CONCAT(forename,' ',surname) AS driver_name,
     year,
     (CONVERT(FLOAT,points)) AS race_points,
     row_number() over (partition by year order by (CONVERT(FLOAT,points)) desc) as rn     
   FROM 
     results AS r    
     INNER JOIN constructors AS c ON r.constructorId = c.constructorId
     INNER JOIN drivers AS d ON r.driverId = d.driverId
     INNER JOIN races AS rc ON r.raceId = rc.raceId
)
SELECT * FROM cte 
WHERE rn = 1

这就是 sub 的样子

driver_name	year	race_points
a	2011	1
a	2011	1
b	2011	2
b	2011	2
c	2012	3
c	2012	3
d	2012	4
d	2012	4

我试图让它看起来像这样

driver_name	year	max_points
b	2011	4
d	2012	8

我目前得到的是这个

driver_name	year	max_points
b	2011	2
d	2012	4

任何帮助将不胜感激。

【问题讨论】：

您没有在 CTE 中汇总您的价值观；添加聚合，您就有了解决方案。
非常感谢

标签： sql sql-server aggregate-functions common-table-expression

【解决方案1】：

您希望使用窗口函数进行聚合：

WITH cte as (
      SELECT CONCAT(forename, ' ', surname) AS driver_name,
             year, SUM(points) as race_points,
             RANK() OVER (PARTITION BY year ORDER BY SUM(points) DESC) as seqnum
      FROM results r JOIN 
           constructors c
           ON r.constructorId = c.constructorId JOIN
           drivers d
           ON r.driverId = d.driverId JOIN
           races rc
           ON r.raceId = rc.raceId
      GROUP BY CONCAT(forename, ' ', surname), year
     )
SELECT *
FROM cte
WHERE seqnum = 1;

【讨论】：