【发布时间】：2018-11-19 18:05:01
【问题描述】：
我有这个问题：
BEGIN
DROP TABLE IF EXISTS `tblquota`;
CREATE TABLE IF NOT EXISTS tblquota (id INT AUTO_INCREMENT PRIMARY KEY) AS
SELECT c.id as user_id
, c.`email`
, h.`packageid` as pack_id
, p.`name` as pack_name
, max(CASE
WHEN `name` = "Basic" THEN '100'
WHEN `name` = "Silver" THEN '100'
WHEN `name` = "Gold" THEN '100'
ELSE '10'
END) as quota
FROM `tblclients` c
LEFT JOIN `tblhosting` h ON c.id = h.userid
INNER JOIN `tblproducts` p ON h.packageid = p.id
ORDER BY c.id;
END
在这种情况下，查询只会获取一位客户的最大值。我想获得每位客户的价值。
表客户：
id | email | status
----------------------------
1 | user1@mail.com | Active
2 | user2@mail.com | Inactive
3 | user3@mail.com | Active
表tblhosting
id | userid | packageid | domainstatus
------------------------------------------------
1 | 1 | 3 | Active
2 | 1 | 2 | Active
3 | 2 | 1 | Active
4 | 2 | 2 | Active
5 | 2 | 3 | Inactive
6 | 3 | 1 | Active
表tblproducts
id | name
-----------
1 | Basic
2 | Silver
3 | Gold
我希望结果如下：
id | user_id | email | pack_id | pack_name | quota
-----------------------------------------------------------
1 | 1 | user1@mail.com | 3 | Gold | 1000
2 | 2 | user2@mail.com | 2 | Silver | 100
3 | 3 | user3@mail.com | 1 | Basic | 10
【问题讨论】：
-
你需要
GROUP BY c.id。