Teradata 语法：Unicode 分隔标识符

Question

尝试在 Teradata 13.0 中运行查询时出错 如何编写此查询？我将此 oracle 查询转换为 Teradata 查询：

select sb.name,
       sb.address1, 
       sb.address2, 
       sb.city, 
       sb.stateprovince,
       sb.postalcode, 
       sb.country, 
       sb.cid, 
       sb.item, 
       sb.mcnum, 
       sb.dmh, 
       sb.hy, 
       sb.firstname, 
       sb.lastname, 
       sb.email, 
       sb.monikerexec, 
       sb.res,
 (select cid from (select * from abc.submissions where res is not null order by res asc) where name = sb.name and item <> sb.item and res < sb.res and rownum =1) as mins,
  (select min(price) from ap.hist where name = sb.name) as minauc,
       sb.cat, 
       sb.uni
 from abc.submission sb
order by sb.item

错误：

Answer 1

听起来问题不在于缺少别名（这是一个问题），而是需要在子查询中使用ORDER BY，以便可以在SELECT 语句中的第一个子查询 minauc。

您可以使用QUALIFY，而不是执行ORDER BY 并尝试获取第一条记录，它使用窗口函数来选择您想要的记录：

SELECT 
    sb.NAME, 
    sb.address1, 
    sb.address2, 
    sb.city, 
    sb.stateprovince, 
    sb.postalcode,
    sb.country, 
    sb.cid, 
    sb.item, 
    sb.mcnum, 
    sb.dmh, 
    sb.hy, 
    sb.firstname, 
    sb.lastname, 
    sb.email, 
    sb.monikerexec, 
    sb.res,
    sb2.cid AS mins, 
    (
        SELECT min(price)
        FROM ap.hist
        WHERE NAME = sb.NAME
    ) AS minauc, 
    sb.cat, 
    sb.uni
FROM abc.submission sb
    LEFT OUTER JOIN abc.Submission sb2 ON
    sb.name = sb2.name AND
    sb.item <> sb.item AND
    sb2.res < sb.res AND
    sb2.res IS NOT NULL
QUALIFY ROW_NUMBER() OVER (PARTITION BY sb.name ORDER BY res asc) = 1

这使用 JOIN 将记录放在一起，然后，使用 QUALIFY 只允许通过具有最低 res 的连接记录。