经过大量研究和实验,看起来libevdev 可能是正确的工具。我开发了下面的程序作为概念验证来绑定Alt+X 以启动xterm。
不幸的是,它必须以 root 身份运行,所以我想我需要以某种方式将它与本地桌面会话联系起来。就我的目的而言,使用 root 用户 setuid 并收工可能就足够了。
我也不相信我的键盘检测启发式方法非常好。我本质上是在寻找任何具有按键和重复率的设备,在我的系统上只匹配我的键盘。
#include <errno.h>
#include <stdlib.h>
#include <stdbool.h>
#include <stdio.h>
#include <string.h>
#include <dirent.h>
#include <fcntl.h>
#include <libevdev/libevdev.h>
#define DEVROOT "/dev/input/"
#define DEVROOT_LEN 12
#define PATH_LEN (DEVROOT_LEN + NAME_MAX)
int outerr(int, const char*);
struct libevdev* open_device(int);
bool kblike(struct libevdev*);
int main(int argc, char* argv[]) {
DIR* dir;
struct dirent* entry;
char path[PATH_LEN];
int fd, err;
struct libevdev* dev = NULL;
struct input_event ev;
bool key, rep, alt;
if (!(dir = opendir("/dev/input"))) {
return outerr(errno, "cannot enumerate devices");
}
// look for keyboard device
while (entry = readdir(dir)) {
if (DT_CHR == entry->d_type) {
sprintf(path, "/dev/input/%s", entry->d_name);
if (-1 == (fd = open(path, O_RDONLY|O_NONBLOCK))) {
return outerr(errno, "cannot read device");
}
if (dev = open_device(fd)) {
if (kblike(dev)) break;
libevdev_free(dev);
dev = NULL;
}
}
}
closedir(dir);
// check if keyboard was found
if (dev == NULL) {
return outerr(ENODEV, "could not detect keyboard");
} else do {
err = libevdev_next_event(dev, LIBEVDEV_READ_FLAG_NORMAL, &ev);
if (err == 0 && ev.type == EV_KEY) switch (ev.code) {
case KEY_LEFTALT:
alt = ev.value == 1;
break;
case KEY_X:
if (ev.value == 1 && alt) system("xterm");
break;
}
} while (err == 1 || err == 0 || err == -EAGAIN);
return 0;
}
int outerr(int errnum, const char* msg) {
fprintf(stderr, "%s (%s)\n", msg, strerror(errnum));
return errnum;
}
bool kblike(struct libevdev* dev) {
return libevdev_has_event_type(dev, EV_KEY)
&& libevdev_has_event_type(dev, EV_REP);
}
struct libevdev* open_device(int fd) {
struct libevdev* dev = libevdev_new();
int err;
if (dev == NULL) {
errno = ENOMEM;
} else if (0 > (err = libevdev_set_fd(dev, fd))) {
libevdev_free(dev);
dev = NULL;
errno = -err;
}
return dev;
}