无法读取数据，因为它的格式不正确 - swift

Question

我在从 URL 请求中读取 JSON 时遇到问题

我的 JSON

{"id" : "screens" ,"title" : "Skærmbilleder" ,"imagepath" : "https://www.spiritbooks.dk/service/menu/screens.png"},{"id" : "presale" ,"title" : "Presale" ,"imagepath" : "https://www.spiritbooks.dk/service/menu/presale.png"},{"id" : "discount" ,"title" : "Rabatkoder" ,"imagepath" : "https://www.spiritbooks.dk/service/menu/discount.png"},{"id" : "contact" ,"title" : "Kontakt" ,"imagepath" : "https://www.spiritbooks.dk/service/menu/contact.png"},{"id" : "about" ,"title" : "Om hjertechakra appen" ,"imagepath" : "https://www.spiritbooks.dk/service/menu/about.png"},

我的代码

        AF.request("myUrl").responseJSON { response in
            if let result = response.data {
                do {
                    // make sure this JSON is in the format we expect
                    if let json = try JSONSerialization.jsonObject(with: result, options: []) as? [[String:Any]] {
                        
                        for categoryData in json{
                            var category = Category()
                            
                            if let id = categoryData["id"] as? String{
                                category.id = id
                            }
                            
                            if let title = categoryData["title"] as? String{
                                category.title = title
                            }
                            if let imagepath = categoryData["imagepath"] as? String{
                                category.imagepath = imagepath
                            }
                            
                            self.categories.append(category)
                        }
                    }
                } catch let error as NSError {
                    print("Failed to load: \(error.localizedDescription)")
                }
                
                
            }
        }
    }
    
}

我收到错误代码“加载失败：无法读取数据，因为它的格式不正确”

Answer 1

您的 JSON 不合法。将其粘贴到jsonlint 中，它会向您显示错误。您的数据似乎是一个 JSON 数组，但它没有包含在 [...] 中。