在matlab中将图像分割成窗口

Question

我正在使用以下决策树来检测图像中的 ROI：http://www.ncbi.nlm.nih.gov/pmc/articles/PMC3097782/figure/F7/。第一部分使用 32x32 窗口使用下面显示的代码扫描整个图像。谁能告诉我如何计算这个窗口内像素的平均强度？谢谢

N = 32;
info = repmat(struct, ceil(size(M, 1) / N), ceil(size(M, 2) / N));
for row = 1:N:size(M, 1)%loop through each pixel in the image matrix
    for col = 1:N:size(M, 2)
        r = (row - 1) / N + 1;
        c = (col - 1) / N + 1;

        imgWindow = M(row:min(end,row+N-1), col:min(end,col+N-1));
        largest = max(imgWindow(:));
        [rLarg, cLarg] = find(imgWindow == largest, 1, 'first');

        window(r, c).largest = largest;
        window(r, c).row = rLarg + row - 1;
        window(r, c).col = cLarg + col - 1;
    end
end

Answer 1

mean 函数计算平均值

average = mean(imgWindow(:));

然后，您可以以与您已经为窗口最大值所做的类似的方式保存每个窗口平均值：

window(r, c).average = average;