【发布时间】:2021-10-22 18:00:02
【问题描述】:
我尝试在第一次检测到硬件中断检测下降沿时激活定时器,并在运行 8 次后停用定时器。但是当我停止定时器时,硬件中断再次触发并立即启动定时器。
在图像中,您可以忽略蓝色信号。紫色信号是定时器 1 切换引脚。绿色是切换引脚的硬件中断。
它所要做的就是在第一个下降沿触发,然后在一段时间内切换一个引脚。
我的问题是:为什么硬件中断会触发两次?
#define F_CPU 16000000UL
#include <avr/io.h>
#include <util/delay.h>
#include <avr/interrupt.h>
volatile int cnt = 0;
uint8_t data[8];
int main(void)
{
// TIMER 1
DDRB |= (1 << PORTB0); // Set LED as output
DDRB |= (1 << PORTB1); // Set LED as output
DDRB |= (1 << PORTB2); // Set LED as output
DDRD &= ~(1 << PORTD2); // Set LED as INPUT
PORTD |= (1 << PORTD2); // PULLUP resistor
TCCR1B |= (1 << WGM12); // Configure timer 1 for CTC mode
TIMSK1 &= ~(1 << OCIE1A); // Disable CTC interrupt
//TIMSK1 |= (1 << OCIE1A); // Enable CTC interrupt
OCR1A = 1200; // Set CTC compare value to 15873Hz at 16MHz AVR clock, with a prescaler of 1
//TCNT0 = 0;
TCCR1B |= ((1 << CS10)); // Start timer at Fcpu/1
// Interrupt
EICRA |= (1 << ISC01) | (1 << ISC11); //ENABLE INT0 and INT1 ON falling EDGE
EIMSK |= (1 << INT0); //ENABLE INT0
EIMSK |= (1 << INT1); //ENABLE INT0
sei(); // Enable global interrupts
while (1)
{
}
}
ISR(TIMER1_COMPA_vect)
{
cnt = cnt + 1;
PORTB ^= (1 << PORTB0); // D8
if (cnt > 7)
{
TIMSK1 &= ~(1 << OCIE1A); // stop CTC interrupt
EIMSK |= (1 << INT0); //Enable INT0
EIMSK |= (1 << INT1); //Enable INT0
return;
}
}
ISR(INT0_vect) //External interrupt_zero ISR
{
EIMSK &= ~(1 << INT0); //Disable INT0
PORTB ^= (1 << PORTB2); // Toggle the LED
TCNT1 = 0;
cnt = 0;
TIMSK1 |= (1 << OCIE1A); // Enable CTC interrupt
}
ISR(INT1_vect) //External interrupt_zero ISR
{
PORTB ^= (1 << PORTB2); // Toggle the LED
EIMSK &= ~(1 << INT1); //Disable INT0
TCNT1 = 0;
cnt = 0;
TIMSK1 |= (1 << OCIE1A); // Enable CTC interrupt
}
【问题讨论】:
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网络搜索:
OCIE1A产生:avrfreaks.net/forum/setting-timsk1-immediately-fires-isr 建议:在启用中断之前尝试清除中断标志,如下(直接写入,不使用逻辑或):TIFR1 = (1<<OCF1A);