{closure}() 缺少参数 2；

Question

我正在使用 Slim 框架处理我的 RESTful Web 服务，当我尝试从 3 个表中获取数据时出现此错误。

这是我课堂上的函数：

public function getCard($card_id, $card_type_id, $user_id) {
    $stmt = $this->conn->prepare("SELECT uc.id, c.card_name, ct.category, c.card_desc, c.card_picture ,c.status, c.created_at from cards c, user_cards uc, cards_type ct WHERE c.card_type_id = ct.card_type_id AND c.card_id = uc.card_id AND uc.user_id = ?");

    if ($stmt == FALSE) {
        die($this->conn->error);
    } else {
        $stmt->bind_param("iii", $card_id, $card_type_id, $user_id);
        if ($stmt->execute()) {
            $res = array();
            $stmt->bind_result($id, $card_name, $category, $card_desc, $card_picture, $status, $created_at);

            $stmt->fetch();
            $res["id"]           = $id;
            $res["card_name"]    = $card_name;
            $res["category"]     = $category;
            $res["card_desc"]    = $card_desc;
            $res["card_picture"] = $card_picture;
            $res["status"]       = $status;
            $res["created_at"]   = $created_at;
            $stmt->close();
            return $res;
        } else {
            return NULL;
        }
    }
}

这是 index.php 中的代码：

$app->get('/cards/users/:card_id', 'authenticate', function($card_id, $card_type_id) {
    global $user_id;
    $response = array();
    $db       = new Card();

    // fetch card
    $result = $db->getCard($card_id, $card_type_id, $user_id);

    if ($result != NULL) {
        $response["error"]        = false;
        $response["id"]           = $result["id"];
        $response["card_name"]    = $result["card_name"];
        $response["category"]     = $result["category"];
        $response["card_desc"]    = $result["card_desc"];
        $response["card_picture"] = $result["card_picture"];
        $response["status"]       = $result["status"];
        $response["createdAt"]    = $result["created_at"];
        echoRespnse(200, $response);
    } else {
        $response["error"]   = true;
        $response["message"] = "The requested resource doesn't exists";
        echoRespnse(404, $response);
    }
});

我写错了吗？

Answer 1

看看这一行：

$stmt = $this->conn->prepare("SELECT uc.id, c.card_name, ct.category, c.card_desc, c.card_picture ,c.status, c.created_at from cards c, user_cards uc, cards_type ct WHERE c.card_type_id = ct.card_type_id AND c.card_id = uc.card_id AND uc.user_id = ?");

查询可能很难看到，所以我将只格式化查询：

SELECT uc.id, 
       c.card_name, 
       ct.category, 
       c.card_desc, 
       c.card_picture, 
       c.status, 
       c.created_at 
FROM   cards c, 
       user_cards uc, 
       cards_type ct 
WHERE  c.card_type_id = ct.card_type_id 
       AND c.card_id = uc.card_id 
       AND uc.user_id = ? 

注意它只有一个问号，表示你应该只绑定一个参数到你准备好的语句。

所以你应该改变这一行：

$stmt->bind_param("i", $user_id); //have only one argument