DuplicateMappingException 表[]包含多个逻辑列名引用的物理列名[]：[_id]、[Id]

Question

我正在重写一个项目，但我遇到了构建问题。

Caused by: org.hibernate.DuplicateMappingException: Table [language] contains physical column name [person_id] referred to by multiple logical column names: [person_id], [personId]

在哪里

@Builder
@Data
@AllArgsConstructor
@NoArgsConstructor
@Entity
@IdClass(LanguagePK.class)
@Table(name = "language")
public class Language {
    @Id
    @Column(name = "person_id")
    private int personId;
    @Id
    @Column(name = "position")
    private int position;
    @Id
    @Column(name = "language_name")
    private String languageNameVal;
    @Column(name = "language_level")
    private String languageLevelVal;
    @ManyToOne
    @JoinColumn(name = "person_id", referencedColumnName = "id", nullable = false, insertable = false,updatable = false)
    @JsonBackReference(value = "languages")
    private Person person;
    @ManyToOne
    @JoinColumn(name = "language_name", referencedColumnName = "name", nullable = false, insertable = false,updatable = false)
    @JsonIgnore
    private LanguageName languageName;
    @ManyToOne
    @JoinColumn(name = "language_level", referencedColumnName = "level", nullable = false, insertable = false,updatable = false)
    @JsonIgnore
    private LanguageLevel languageLevel;
}

和

@Builder
@Data
@NoArgsConstructor
@AllArgsConstructor
@Entity
@Table(name = "person")
public class Person implements Serializable{
private static final long serialVersionUID = 1L;
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "id")
    private int id;

@JsonManagedReference(value = "languages")
    @OneToMany(mappedBy = "person", cascade = {CascadeType.PERSIST, CascadeType.MERGE})
    private Set<Language> languages;

我用

• 休眠版本 5.4.13.Final
• spring-boot v. 2.2.5.RELEASE
• 分级
• java 1.8
• 龙目岛

这些变化非常小，就像我使用 maven、SessionFactory 用于休眠、传统的 getter 和 setter 之前一样。

我在 hibernate 4 和 5 之间的迁移过程中看到了一些类似的问题，其中 NamingStrategy 是一个问题，但是此代码适用于 hiberante 为 5.4.10.Final 的第一个项目。

我喜欢 IdClass，因为我可以将 personId 作为原始值访问，并且不必从对象 person 加载数据。

我在没有insertable = false,updatable = false 的情况下看到了类似的问题，但我有它......

发现类似问题here

Answer 1

解决方案

问题在于访问策略字段与属性访问。

在之前的项目中，一切都是基于属性的访问，但在我添加 lombok 之后，Language 类是基于字段的访问。

LanguagePK 的班级是

public class LanguagePK implements Serializable {
    private static final long serialVersionUID = 1L;
    private int personId;
    private int position;
    private String languageNameVal;

    @Column(name = "person_id")
    @Id
    public int getPersonId() {
        return personId;
    }

    public void setPersonId(int personId) {
        this.personId = personId;
    }

    @Column(name = "position")
    @Id
    public int getPosition() {
        return position;
    }

    public void setPosition(int position) {
        this.position = position;
    }

    @Column(name = "language_name")
    @Id
    public String getLanguageNameVal() {
        return languageNameVal;
    }

    public void setLanguageNameVal(String languageNameVal) {
        this.languageNameVal = languageNameVal;
    }

    @Override
    public boolean equals(Object o) {
        if (this == o) return true;
        if (o == null || getClass() != o.getClass()) return false;

        LanguagePK that = (LanguagePK) o;

        if (personId != that.personId) return false;
        if (position != that.position) return false;
        if (languageNameVal != null ? !languageNameVal.equals(that.languageNameVal) : that.languageNameVal != null)
            return false;

        return true;
    }

    @Override
    public int hashCode() {
        int result = personId;
        result = 31 * result + position;
        result = 31 * result + (languageNameVal != null ? languageNameVal.hashCode() : 0);
        return result;
    }
}

够用了

@EqualsAndHashCode
public class EducationPK implements Serializable {
    private int personId;
    private int position;
}