【发布时间】:2021-07-05 06:15:35
【问题描述】:
考虑下面给定的xml:
<?xml version="1.0"?>
<Records>
<Record>
<Prop name="commerce">sku1</Prop>
<Prop name="commerce">sku2</Prop>
<Prop name="commerce">sku3</Prop>
<Prop name="commerce">sku4</Prop>
</Record>
<Record>
<Prop name="commerce">sku10</Prop>
<Prop name="commerce">sku20</Prop>
<Prop name="commerce">sku30</Prop>
<Prop name="commerce">sku40</Prop>
</Record>
</Records>
现在考虑一下我创建的这些 Pojos(为简洁起见,删除了 getter 和 setter)。
public class Records {
private List<Record> records;
}
public class Record {
private List<Prop> props;
}
public class Prop {
// I want to capture name attribute
private String name;
// But I also want to capture what comes inside Prop element as well. This would then have values like sku1, sku2 etc
private String text;
}
现在我有了像这样使用 XMLWrapper 的代码。
File file = ResourceUtils.getFile("classpath:sample.xml"); // the above XML is sample.xml
XmlMapper xmlMapper = XmlMapper.builder().build();
Records records = xmlMapper.readValue(file, Records.class); // this line is failing
但是我遇到了这样的错误
Caused by: com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field "Record" (class com.example.demo.model.xml.Records), not marked as ignorable (one known property: "records"])
【问题讨论】:
-
应该是
@XmlElement(name = "Record") private List<Record> records;以匹配元素名称。Prop的主体相同
标签: java xml jackson xml-deserialization fasterxml