【问题标题】:XML deserialization to POJO using Jackson XmlMapper使用 Jackson XmlMapper 将 XML 反序列化为 POJO
【发布时间】:2014-10-22 18:39:50
【问题描述】:

使用 Jackson XmlMapper 注释,我如何将此 XML 反序列化为 pojo?

<?xml version="1.0" encoding="UTF-8"?>
<open>
   <creds priv="write" type="internal">
      <user>Username1</user>
      <client_token>abcplaudzrbcy37c</client_token>
      <client_secret>0cxDE3LE0000=</client_secret>
   </creds>
   <creds priv="read" type="internal">
      <user>Username1</user>
      <client_token>123plaudzrbcy37c</client_token>
      <client_secret>0cxDE3LE1234=</client_secret>
   </creds>
   <creds priv="none" type="internal">
      <user>Username1</user>
      <client_token>000plaudzrbcy37c</client_token>
      <client_secret>0cxDE3LEabcd=</client_secret>
   </creds>
</open>

我尝试使用这样的东西:

@JacksonXmlRootElement(localName = "Open")
public class OpenCredentials {

    @JacksonXmlProperty(localName = "Credentials")
    private Credentials[] credentials;

}


class Credentials {

    @JacksonXmlProperty(isAttribute = true)
    private String priv;

    @JacksonXmlProperty(isAttribute = true)
    private String type;

    @JacksonXmlProperty(localName = "Creds")
    private Creds[] creds;
}


class Creds {

    @JacksonXmlText(value = true)
    private String user;

    @JacksonXmlText(value = true)
    private String client_token;

    @JacksonXmlText(value = true)
    private String client_secret;
}

当我尝试使用 XmlMapper 的 readValue() 时,出现以下错误:

com.fasterxml.jackson.databind.JsonMappingException: Duplicate property '' for [simple type, class com.company.data.utils.api.Creds]
at com.fasterxml.jackson.databind.deser.DeserializerCache._createAndCache2(DeserializerCache.java:268)
at com.fasterxml.jackson.databind.deser.DeserializerCache._createAndCacheValueDeserializer(DeserializerCache.java:243)

【问题讨论】:

    标签: java xml jackson deserialization


    【解决方案1】:

    您的POJO 课程不适合您的XML。结构比你想象的要简单。见下例:

    @JacksonXmlRootElement(localName = "open")
    class OpenCredentials {
    
        @JacksonXmlProperty(localName = "creds")
        @JacksonXmlElementWrapper(useWrapping = false)
        private Credentials[] credentials;
    
        //getters, setters, toString
    }
    
    
    class Credentials {
    
        @JacksonXmlProperty(isAttribute = true)
        private String priv;
    
        @JacksonXmlProperty(isAttribute = true)
        private String type;
    
        private String user;
    
        @JacksonXmlProperty(localName = "client_token")
        private String clientToken;
    
        @JacksonXmlProperty(localName = "client_secret")
        private String clientSecret;
    
        //getters, setters, toString
    }
    

    简单用法:

    XmlMapper mapper = new XmlMapper();
    OpenCredentials openCredentials = mapper.readValue(XML, OpenCredentials.class);
    System.out.println(openCredentials);
    

    上面的程序打印(为您的XML):

    OpenCredentials{credentials=[Credentials{priv='write', type='internal', user='Username1', client_token='abcplaudzrbcy37c', client_secret='0cxDE3LE0000='}, Credentials{priv='read', type='internal', user='Username1', client_token='123plaudzrbcy37c', client_secret='0cxDE3LE1234='}, Credentials{priv='none', type='internal', user='Username1', client_token='000plaudzrbcy37c', client_secret='0cxDE3LEabcd='}]}
    

    另见:

    1. jackson-dataformat-xml
    2. Home: Jackson XML databind Wiki

    【讨论】:

    • 我得到“无法识别的字段”将 localName 设置为 JacksonXmlElementWrapper 注释,拆分为 @MichalZiober 示例后,反序列化工作正常
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