【发布时间】:2018-05-17 13:36:01
【问题描述】:
如果我不在映射方法上使用@JsonIgnore 注释,我在获取数据时会收到此异常
at com.fasterxml.jackson.databind.ser.std.BeanSerializerBase.serializeFields(BeanSerializerBase.java:678)
at com.fasterxml.jackson.databind.ser.BeanSerializer.serialize(BeanSerializer.java:157)
at com.fasterxml.jackson.databind.ser.std.CollectionSerializer.serializeContents(CollectionSerializer.java:149)
at com.fasterxml.jackson.databind.ser.std.CollectionSerializer.serialize(CollectionSerializer.java:112)
at com.fasterxml.jackson.databind.ser.std.CollectionSerializer.serialize(CollectionSerializer.java:25)
at com.fasterxml.jackson.databind.ser.BeanPropertyWriter.serializeAsField(BeanPropertyWriter.java:672)
at com.fasterxml.jackson.databind.ser.std.BeanSerializerBase.serializeFields(BeanSerializerBase.java:678)
at com.fasterxml.jackson.databind.ser.BeanSerializer.serialize(BeanSerializer.java:157)
at com.fasterxml.jackson.databind.ser.BeanPropertyWriter.serializeAsField(BeanPropertyWriter.java:672)
at com.fasterxml.jackson.databind.ser.std.BeanSerializerBase.serializeFields(BeanSerializerBase.java:678)
at com.fasterxml.jackson.databind.ser.BeanSerializer.serialize(BeanSerializer.java:157)
at com.fasterxml.jackson.databind.ser.std.CollectionSerializer.serializeContents(CollectionSerializer.java:149)
at com.fasterxml.jackson.databind.ser.std.CollectionSerializer.serialize(CollectionSerializer.java:112)
at com.fasterxml.jackson.databind.ser.std.CollectionSerializer.serialize(CollectionSerializer.java:25)
at com.fasterxml.jackson.databind.ser.BeanPropertyWriter.serializeAsField(BeanPropertyWriter.java:672)
at com.fasterxml.jackson.databind.ser.std.BeanSerializerBase.serializeFields(BeanSerializerBase.java:678)
at com.fasterxml.jackson.databind.ser.BeanSerializer.serialize(BeanSerializer.java:157)
请看实体类
package com.rasvek.cg.entity;
// Generated May 14, 2018 11:39:07 PM by Hibernate Tools 5.1.7.Final
import java.util.HashSet;
import java.util.Set;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.FetchType;
import javax.persistence.GeneratedValue;
import static javax.persistence.GenerationType.IDENTITY;
import javax.persistence.Id;
import javax.persistence.OneToMany;
import javax.persistence.Table;
import com.fasterxml.jackson.annotation.JsonIgnore;
/**
* MasterCampusClass generated by hbm2java
*/
@Entity
@Table(name = "master_campus_class", catalog = "campus_guru_01")
public class MasterCampusClass implements java.io.Serializable {
private Integer classId;
private String className;
private String classShortName;
@Id
@GeneratedValue(strategy = IDENTITY)
@Column(name = "class_id", unique = true, nullable = false)
public Integer getClassId() {
return this.classId;
}
public void setClassId(Integer classId) {
this.classId = classId;
}
@Column(name = "class_name")
public String getClassName() {
return this.className;
}
public void setClassName(String className) {
this.className = className;
}
@Column(name = "class_short_name")
public String getClassShortName() {
return this.classShortName;
}
//@JsonIgnore
@OneToMany(fetch = FetchType.EAGER, mappedBy = "masterCampusClass")
public Set<MasterCampusSection> getMasterCampusSections() {
return this.masterCampusSections;
}
public void setMasterCampusSections(Set<MasterCampusSection> masterCampusSections) {
this.masterCampusSections = masterCampusSections;
}
}
如果我使用 @JsonIgnore ,当我保存 MasterCampusSections 不接受 json 时,由于 @jsonIgnore 注释,它不会作为 json 接收
不使用@JsonIgnore注解就不能解决上面的异常吗?
如果可能,请告诉我!谢谢。
【问题讨论】:
-
我们可以在那里抛出
Exception的类型。您的堆栈跟踪以at com.fasterxml.jackson.databind开头,这些行的某处是异常本身。它可能对我们有帮助。
标签: java hibernate hibernate-mapping