intelliSense：没有重载函数“sqrt”的实例与参数列表参数类型匹配：(double *)

Question

这段代码有什么问题？？！！！我正在制作一个程序试图解决二次方程并看到这个错误并且无法解决它我应该改为浮动还是什么？？

#include<stdio.h>
#include<conio.h>
#include<math.h>

void solve_quadratic(double a,double b,double c ,double *d ,double *r1,double *r2);
int main (void)
{
double x,y,z;
double root1,root2;
double desc;
printf("Enter the value of a:  ");
scanf("%lf",&x);
printf("Enter the value of b :  ");
scanf("%lf",&y);
printf("Enter the value of c :   ");
scanf("%lf",&z);

solve_quadratic(x,y,z,&desc,&root1,&root2);
if (desc<0)
{
    printf("No Result !!!");
}
else if (desc>0)
{
    printf("The value of the first root = %f \n",root1);
    printf("The value of the second root = %f  \n",root2);
}
getch();
return 0;

}

void solve_quadratic(double a,double b,double c ,double *d ,double *r1,double *r2)
{
*d=b*b-4*a*c;
if (d>=0)
{
    *r1=(-b+sqrt(d))/(2*a);
    *r2=(-b-sqrt(d))/(2*a);
}
}

Answer 1

*r1=(-b+sqrt(d))/(2*a);     <<<< d is pointer not double.

您正在将指向 double 的指针传递给 sqrt。应该是：-

*r1=(-b+sqrt(*d))/(2*a);