我已将函数简化为专注于char** 参数。在编写示例函数时,它假定内存是预先分配的,但是没有接口来指示用于输出的数组的大小或数组中的各个字符串。在这个例子中,内存是为一个 3 元素数组预先分配的,每个字符串最多 20 个字符,但实际上用户必须预先分配足够长的字符串来保存实际的返回值-生活状况。
test.cpp:
#define API __declspec(dllexport)
#include <vector>
#include <string>
#include <cstring>
using namespace std;
//This method takes filename as input and oNames as output
extern "C" API void GetNames(char** oNames)
{
vector<string> names { "one", "two", "three" };
for (size_t i = 0; i < names.size(); ++i) {
strcpy(oNames[i], names[i].c_str());
}
}
test.py:
from ctypes import *
dll = CDLL('./test')
dll.GetNames.argtypes = POINTER(c_char_p),
dll.GetNames.restype = None
def get_names():
ARR3 = c_char_p * 3 # equivalent to char*[3] type in C
# list of 3 mutable pointers to buffers
buffers = [cast(create_string_buffer(20),c_char_p) for _ in range(3)]
names = ARR3(*buffers) # array initalized with buffers
dll.GetNames(names)
return list(names)
print(get_names())
输出:
[b'one', b'two', b'three']
如果您可以随意更改 API,那么动态分配内存以便稍后释放可以使其更加灵活。这对于 char*** 来说相当难看,但它可以工作:
test.cpp:
#define API __declspec(dllexport)
#include <vector>
#include <string>
#include <cstring>
using namespace std;
extern "C" {
API void GetNames(char*** oNames) {
vector<string> names { "one", "two", "three" };
auto arr = new char*[names.size() + 1];
for (size_t i = 0; i < names.size(); ++i) {
auto len = names[i].size() + 1;
arr[i] = new char[len];
strcpy_s(arr[i], len, names[i].c_str());
}
arr[names.size()] = nullptr;
*oNames = arr;
}
API void FreeNames(char** names) {
if(names) {
for(size_t i = 0; names[i]; ++i)
delete [] names[i];
delete [] names;
}
}
}
test.py:
from ctypes import *
# ctypes.c_char_p has special handling for strings,
# but hides the pointer value. Deriving a type
# from c_char_p prevents this special handling
# and allows access to the pointer, so we can later
# free it.
class PCHAR(c_char_p):
pass
dll = CDLL('./test')
dll.GetNames.argtypes = POINTER(POINTER(PCHAR)),
dll.GetNames.restype = None
dll.FreeNames.argtypes = POINTER(PCHAR),
dll.FreeNames.restype = None
def get_names():
pnames = POINTER(PCHAR)() # allocate char**
dll.GetNames(byref(pnames)) # pass char***
i = 0
names = []
while pnames[i]: # returned char* array is terminated with null
names.append(pnames[i].value) # create and save the Python byte string
i += 1
dll.FreeNames(pnames)
return names
print(get_names())
输出:
[b'one', b'two', b'three']