mysqli_fetch_array() 期望参数 1 为 mysqli_result，布尔值在 C:\xampp\htdocs\wst\admin1.php 第 297 行 [重复]

Question

我想添加 2 行包含数字的表格，并且我希望在表格的新行中添加 2 行的总和

我使用 sql 查询编写了我的代码..

<?php
    $con =  mysqli_connect("localhost", "root", "", "project");
    if(!$con) {
      die('not connected');
    }
    $con =  mysqli_query($con, "SELECT addplace, stayamount, foodamount, airlinesamount, noofdays, totalamount AS sum(stayamount + foodamount + airlinesamount) choose FROM adddetails");

?>
<div class="container">
  <center><h2>view packages</h2></center>  
  <table class="table table-bordered">
    <th>place</th>
    <th>stay cost</th>
    <th>food cost</th>
    <th>flight cost</th>
    <th>no of days</th>
    <th>total amount</th>
    <th>image</th>

    <?php while($row = mysqli_fetch_array($con, MYSQLI_ASSOC)) { ?>
    <tr>
      <td><?php echo $row['addplace']; ?></td>
      <td><?php echo $row['stayamount']; ?></td>
      <td><?php echo $row['foodamount'] ;?></td>
      <td><?php echo $row['airlinesamount'] ;?></td>
      <td><?php echo $row['noofdays'] ;?></td>
      <td><?php echo $row['totalamount'] ;?></td>
      <td><?php echo $row['choose'] ;?></td>
    </tr>
    <?php } ?>
  </table>
</div>

我收到一个错误。

任何人都可以重写我的 sql 查询或 php 以添加 2 行包含数字的行，我希望将这些行的总和放在一个新行中

[phpmyadmin 中的数据库镜像][1]

[我网页中的表格（图片）][2]

谢谢你

图片代码

<input  name="choose"  class="form-control" type="file" >

我希望将所选图像作为完整图像显示在我的网站上，而不是图像的名称 我该怎么办..

[在选择的行中存储图像][3]

Answer 1

如下更改您的mysql 查询并尝试。我正在考虑packageid 是primary 键

SELECT addplace, stayamount, foodamount, airlinesamount, noofdays, 
    SUM(stayamount + foodamount + airlinesamount) AS totalamount, choose
FROM adddetails GROUP BY packageid

Answer 2

虽然这不是问题的根源，但用结果覆盖 $con 变量并不好。而是使用$result 来存储mysqli_query() 的结果

<?php
    $con = mysqli_connect("localhost", "root", "", "project");
    if(!$con) {
      die('not connected');
    }

    $result = mysqli_query($con, "SELECT addplace, stayamount, foodamount, airlinesamount, noofdays, totalamount AS sum(stayamount + foodamount + airlinesamount) choose FROM adddetails");
    print_r($result); # make sure u have expected output here, if it works delete this line

?>
<div class="container">
  <center><h2>view packages</h2></center>  
  <table class="table table-bordered">
    <th>place</th>
    <th>stay cost</th>
    <th>food cost</th>
    <th>flight cost</th>
    <th>no of days</th>
    <th>total amount</th>
    <th>image</th>

    <?php while($row = mysqli_fetch_assoc($result)) { ?>
    <tr>
      <td><?php echo $row['addplace']; ?></td>
      <td><?php echo $row['stayamount']; ?></td>
      <td><?php echo $row['foodamount'] ;?></td>
      <td><?php echo $row['airlinesamount'] ;?></td>
      <td><?php echo $row['noofdays'] ;?></td>
      <td><?php echo $row['totalamount'] ;?></td>
      <td><?php echo $row['choose'] ;?></td>
    </tr>
    <?php } ?>
  </table>
</div>