编写查询以查找至少租用一部电影并属于阿灵顿市的客户的全名

Question

我收到一条错误消息，提示输出与给定问题不匹配

萨基拉 DB：https://dev.mysql.com/doc/sakila/en/sakila-structure.html

下面是我的代码

with temp as (
select concat(b.first_name, ' ',b.last_name) as name,
count(a.rental_id >= 1) as rental_count
from rental a
inner join customer b ON   (a.customer_id=b.customer_id)
inner join address c ON    (b.address_id=c.address_id)
inner join city d ON       (c.city_id=d.city_id)
where d.city like "Arlington"
group by name
order by rental_count
)
select name from temp

预期结果是

full names of those customers who have rented at least one movie and belong to the city Arlington.

请告诉我是什么错误或有其他方法吗？

Answer 1

您可以使用having 子句，尝试以下操作

select 
    concat(b.first_name, ' ',b.last_name) as name
from rental a
inner join customer b 
on a.customer_id = b.customer_id
inner join address c    
on b.address_id = c.address_id
inner join city d       
on c.city_id = d.city_id
where d.city = 'Arlington'
group by 
    concat(b.first_name, ' ',b.last_name)
having count(a.rental_id) >= 1

Answer 2

select concat(first_name," ", last_name) as Customer_name
from rental
inner join customer
using (customer_id)
inner join address
using(address_id)
inner join city
using (city_id)
where city = "Arlington"
group by Customer_name
having count(rental_id) > 0