写一个查询，查找租借科幻电影2次以上的客户全名并按字母顺序排列答案

【问题标题】：Write a query to find the full names of customers who have rented sci-fi movies more than 2 times and arrange alphabetically写一个查询，查找租借科幻电影2次以上的客户全名并按字母顺序排列
【发布时间】：2020-08-02 07:22:00
【问题描述】：

我正在尝试回答上述问题，但我的输出与预期输出不同。我的代码如下所示，

select distinct concat(first_name, ' ', last_name) as Customer_name
from customer c
inner join rental r on r.customer_id = c.customer_id
inner join inventory i on i.inventory_id = r.inventory_id
inner join film f on f.film_id = i.film_id
inner join film_category fc on fc.film_id = f.film_id
inner join category ca on ca.category_id = fc.category_id
where name = 'sci-fi' and rental_id > 2
order by Customer_name

【问题讨论】：

欢迎来到 Stack Overflow。请通过tour 了解 Stack Overflow 的工作原理，并阅读How to Ask 了解如何提高问题的质量。然后查看meta.stackoverflow.com/questions/333952/… 了解与 SQL 相关的问题。

标签： mysql mysql-workbench

【解决方案1】：

按客户名称聚合，然后从 HAVING 子句断言 2 或更大的计数：

select concat(first_name, ' ', last_name) as Customer_name
from customer c
inner join rental r on r.customer_id = c.customer_id
inner join inventory i on i.inventory_id = r.inventory_id
inner join film f on f.film_id = i.film_id
inner join film_category fc on fc.film_id = f.film_id
inner join category ca on ca.category_id = fc.category_id
where name = 'sci-fi' and rental_id > 2
group by Customer_name
having count(*) > 2
order by Customer_name;

【讨论】：

嗨，蒂姆，have 子句给我一个错误 1064。知道如何纠正吗？
@CodeJunkie Typo 在我的回答中。请重新加载页面并重试。