【发布时间】:2015-06-14 15:13:19
【问题描述】:
我想在 2 个实体之间有一个 JoinTable,这两个实体派生自同一个所有者实体。因此,当使用@ManyToMany 关系加入这些实体时,我得到了@JoinTable(如下面的 DDL):
CREATE TABLE IF NOT EXISTS `local_services`.`service_provided_on` (
`provider_id` INT UNSIGNED NOT NULL,
`service_id` INT UNSIGNED NOT NULL,
`service_point_no` INT UNSIGNED NOT NULL,
`work_station_no` INT UNSIGNED NOT NULL,
PRIMARY KEY (`provider_id`, `service_id`, `service_point_no`, `work_station_no`),
INDEX `fk_provider_service_has_work_station_work_station1_idx` (`service_point_no` ASC, `work_station_no` ASC, `provider_id` ASC),
INDEX `fk_provider_service_has_work_station_provider_service1_idx` (`provider_id` ASC, `service_id` ASC),
CONSTRAINT `fk_service_provided_on_provider_service`
FOREIGN KEY (`provider_id` , `service_id`)
REFERENCES `local_services`.`provider_service` (`provider_id` , `service_id`)
ON DELETE CASCADE
ON UPDATE CASCADE,
CONSTRAINT `fk_service_provided_work_station`
FOREIGN KEY (`service_point_no` , `work_station_no` , `provider_id`)
REFERENCES `local_services`.`work_station` (`service_point_no` , `work_station_no` , `provider_id`)
ON DELETE CASCADE
ON UPDATE CASCADE)
ENGINE = InnoDB
如您所见,有 2 个外键,每个外键都使用相同的 provider_id 列。我想使用这个@JoinTable 来定义由给定提供者提供的属于它 WorkPlace (WorkStation) 的服务。很明显,由具有 id ex 的提供商提供的服务。 5 只能在属于 id 为 5 的提供者的工作场所提供。所以最好在每个 ForeignKey 之间共享这个 @JoinColumn。例如,当尝试插入与提供者 ID 不匹配的工作场所/服务以引发一些异常时!
我尝试做这样的事情:
@ManyToMany(fetch = FetchType.LAZY)
@JoinTable(name = "service_provided_on",
joinColumns = {
@JoinColumn(name = "provider_id", referencedColumnName = "provider_id", nullable = false, columnDefinition = "BIGINT UNSIGNED"),
@JoinColumn(name = "service_id", referencedColumnName = "service_id", nullable = false, columnDefinition = "INT UNSIGNED")
},
inverseJoinColumns = {
@JoinColumn(name = "provider_id", referencedColumnName = "provider_id", insertable = false, updatable = false),
@JoinColumn(name = "service_point_no", referencedColumnName = "service_point_no", nullable = false, columnDefinition = "INT UNSIGNED"),
@JoinColumn(name = "work_station_no", referencedColumnName = "work_station_no", nullable = false, columnDefinition = "INT UNSIGNED")
}
)
但它显然不起作用并引发这样的异常:
Caused by: org.hibernate.MappingException: Repeated column in mapping for collection: pl.salonea.entities.WorkStation.providedServices column: provider_id"}}
我考虑为这个 provider_id 前的一个外键重命名。 work_station_provider_id 但随后我将被允许插入不匹配的 provider_ids,也许我可以定义一些 CONSTRAINT 来阻止这种行为(如何在 JPA 中定义它?)。它可以工作,但我将拥有具有相同 provider_id 的冗余列
【问题讨论】:
标签: hibernate jpa many-to-many entities jointable