【发布时间】:2026-02-08 13:55:01
【问题描述】:
我有一个小的 php 文件,它只是在数据库中创建表。我花了几天时间尝试调试它,这让我很困惑。当我执行查询时,它会弹出一个丑陋的HTTP Error 500 (Internal Server Error): An unexpected condition was encountered while the server was attempting to fulfil the request.。 但是,当我打印出查询并将它们粘贴到数据库中时,它工作正常。
我还注意到手动输入查询时“表已存在”会闪烁,但会消失并快速工作。类似于这个问题 Mysql 1050 Error "Table already exists" when in fact, it does not ,但我尝试删除和重建数据库但没有成功。如果有人可以提供帮助,将不胜感激。这是php代码
$users = 'CREATE TABLE users (
id int UNSIGNED NOT NULL AUTO_INCREMENT,
PRIMARY KEY(id),
username varchar(30) NOT NULL, UNIQUE(username),
password varchar(30) NOT NULL,
email varchar(50) NOT NULL, UNIQUE(email),
confirmation_code int NOT NULL,
confirmation_tries int NOT NULL
) ENGINE=InnoDB';
$players = 'CREATE TABLE players (
id int UNSIGNED NOT NULL,
FOREIGN KEY(id) REFERENCES users(id),
cost int UNSIGNED NOT NULL,
strategy TINYINT UNSIGNED NOT NULL,
age int UNSIGNED NOT NULL,
%s
) ENGINE=InnoDB';
$records = array();
for ($i = 0; $i < NUM_RECORDS; $i++) {
$records[$i] = sprintf('record_%d int UNSIGNED NOT NULL', $i);
}
$players = sprintf($players, implode(', ', $records));
$kingdoms = 'CREATE TABLE kingdoms (
id int UNSIGNED NOT NULL,
FOREIGN KEY(id) REFERENCES users(id),
location int UNSIGNED NOT NULL,
building text NOT NULL,
level int UNSIGNED NOT NULL,
troops int UNSIGNED NOT NULL
) ENGINE=InnoDB';
$inboxes = 'CREATE TABLE inboxes (
recipientID int UNSIGNED NOT NULL,
FOREIGN KEY(recipientID) REFERENCES users(id),
messageID int UNSIGNED NOT NULL AUTO_INCREMENT,
PRIMARY KEY(messageID),
message text NOT NULL,
date DATETIME NOT NULL
) ENGINE=InnoDB';
$lastActions = 'CREATE TABLE last_actions (
id int UNSIGNED NOT NULL,
FOREIGN KEY(id) REFERENCES users(id),
history text
) ENGINE=InnoDB';
$news = 'CREATE TABLE news (
id int UNSIGNED NOT NULL,
FOREIGN KEY(id) REFERENCES users(id),
entries text
) ENGINE=InnoDB';
/*
$dbh->exec($users);
$code = $dbh->errorCode();
if ($code !== '00000') {
var_dump($code);
echo '111111';
exit;
}
$dbh->exec($players);
$code = $dbh->errorCode();
if ($code !== '00000') {
var_dump($code);
echo '22222';
exit;
}
$dbh->exec($kingdoms);
$code = $dbh->errorCode();
if ($code !== '00000') {
var_dump($code);
echo '33333';
exit;
}
$dbh->exec($inboxes);
$code = $dbh->errorCode();
if ($code !== '00000') {
var_dump($code);
echo '44444';
exit;
}
$dbh->exec($lastActions);
$code = $dbh->errorCode();
if ($code !== '00000') {
var_dump($code);
echo '555555';
exit;
}
$dbh->exec($news);//
$code = $dbh->errorCode();
if ($code !== '00000') {
var_dump($code);
echo '666666';
exit;
}//*/
echo $users . ";" . $players . ";" . $kingdoms . ';' . $inboxes . ';' . $lastActions .';' . $news;
【问题讨论】:
-
添加错误报告(E_ALL | E_STRICT); ini_set('display_errors', 1);到你的 PHP 文件的开头,看看发生了什么。
-
这不是你的 SQL 本身给出的错误:检查你的错误日志,它可能是你的 PHP 代码、你的 htaccess 等中的东西。你应该 a) 检查你的错误日志是否有错误, b) 向我们展示一段最小的具有行为的代码,而不是这个大的东西(大部分都被注释掉了?)
-
@MaxSem 谢谢 - 又花了几个小时,但最终解决了这个问题。我的主人发生了一些时髦的事情。如果您想发布作为答案,我会选择它作为正确的