查找序列词 SQL

Question

我使用的是 SQL Server 2008，我需要在 Words 表中搜索完整的句子。

Words

ID          LineNum     WordText
----------- ----------- -----------
1           1           i
2           1           love
3           2           i
4           2           love
5           2           ice
6           3           i
7           3           love
8           3           dogs
9           3           too

如果句子是“我爱狗”，那么这种情况下的结果应该只有 ID 6-8。

ID          LineNum     WordText
----------- ----------- ------------
6           3           i
7           3           love
8           3           dogs

Answer 1

试试这个：

SELECT T1.linenum, 
       word = STUFF((
          SELECT ' ' + T2.wordtext
          FROM TableName T2
          WHERE T1.linenum = T2.linenum
          FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'), 1, 1, '')
FROM TableName T1
GROUP BY T1.linenum
ORDER BY T1.linenum

结果：

LINENUM     WORD
----------------------------
1           i love
2           i love ice
3           I love dogs too

在SQL Fiddle 中查看结果。

编辑：

对于作为列表的结果，这是我能想到的最好的：

WITH CTE AS 
(SELECT T1.linenum
    , word = STUFF((
          SELECT ' ' + T2.wordtext
          FROM TableName T2
          WHERE T1.linenum = T2.linenum
          FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'), 1, 1, '')
FROM TableName T1
GROUP BY T1.linenum)
SELECT T3.*
FROM CTE JOIN
TableName T3 ON CTE.linenum=T3.linenum
WHERE CTE.word LIKE '%I love dogs%'

结果：

ID  LINENUM WORDTEXT
6   3       I
7   3       love
8   3       dogs
9   3       too

SQL Fiddle 中的示例结果。

Answer 2

为此，您需要一个拆分器功能。阅读 Jeff Moden 的 article，了解目前最快的分离器之一。

首先，您要将WordText 与相同的LineNum 连接以生成句子并检查连接的WordTexts 是否包含@sentence 参数。然后，您只能从 Words 表中获取 WordTexts，其中包含 @sentence 中的单词。

DECLARE @sentence VARCHAR(8000) = 'i love dogs'
DECLARE @delimiter CHAR(1) = ' '

;WITH CTE AS(
    SELECT 
        w1.LineNum,
        Sentence = STUFF((
            SELECT ' ' + w2.WordText
            FROM Words w2
            WHERE w1.LineNum = w2.LineNum
            FOR XML PATH(''), TYPE).value('.', 'VARCHAR(MAX)'), 
        1, 1, '')
    FROM Words w1
    GROUP BY w1.LineNum
)
SELECT w.*
FROM CTE c
INNER JOIN Words w
    ON w.LineNum = c.LineNum
INNER JOIN dbo.DelimitedSplit8K(@sentence, @delimiter) d
    ON d.Item = w.WordText
WHERE c.Sentence LIKE '%' + @sentence + '%'
ORDER BY w.ID

SQL Fiddle

结果

ID          LineNum     WordText
----------- ----------- ----------
6           3           i
7           3           love
8           3           dogs

Answer 3

在这里，我将给定的单词分成列并存储到表中。并通过使用count 和partition by 来计算单词，并通过匹配给定文本的单词数来加入主表。

我已使用此答案将文本拆分为表格列。

 declare @commavalue varchar(50)='I love dogs'
 declare @table1 table(id int identity(1,1), wordtext varchar(30))

 insert into @table1

 select q2.value from
 (
   SELECT cast('<x>'+replace(@commavalue,'','</x><x>')+'</x>' as xml) 
   as Data
 ) q1 

 CROSS APPLY

 (
   SELECT x.value('.','varchar(100)') as value 
   FROM Data.nodes('x') as f(x)
 ) q2

declare @table table(id int identity(1,1), linenum int, wordtext varchar(30))

insert into @table values( 1, 'i' )
insert into @table values( 1, 'love')
insert into @table values( 2, 'i' )
insert into @table values( 2, 'love')
insert into @table values( 2, 'ice')
insert into @table values( 3, 'i')
insert into @table values( 3, 'love' )
insert into @table values( 3, 'dogs')
insert into @table values( 3, 'too' )

select t.* from
(
 select t1.linenum, 
 count(t1.wordtext) over(partition by t1.linenum order by t1.id) wordCount
 from @table t1  
 join @table1 t2 on t1.wordtext = t2.wordtext
)
 wc
 join @table t on wc.linenum = t.linenum
 join @table1 t1 on t.wordtext = t1.wordtext
where wordcount = (select count(1) from @table1)