我有一个名为sequence 的列。此列中的数据看起来像 1、2、3、4、5、7、9、10、15。
我需要从表中找到缺失的序列号。什么 SQL 查询会从我的表中找到缺失的序列号？我期待这样的结果
Missing numbers
---------------
6
8
11
12
13
14
我只使用一张桌子。我尝试了下面的查询，但没有得到我想要的结果。
select de.sequence + 1 as sequence from dataentry as de
left outer join dataentry as de1 on de.sequence + 1 = de1.sequence
where de1.sequence is null order by sequence asc;
【问题讨论】：
标签： sql-server-2005 gaps-and-islands
怎么样：
select (select isnull(max(val)+1,1) from mydata where val < md.val) as [from],
md.val - 1 as [to]
from mydata md
where md.val != 1 and not exists (
select 1 from mydata md2 where md2.val = md.val - 1)
给出总结结果：
from to
----------- -----------
6 6
8 8
11 14
【讨论】：
我知道这是一篇很老的帖子，但我想添加这个我找到的解决方案 HERE 以便我可以更轻松地找到它：
WITH Missing (missnum, maxid)
AS
(
SELECT 1 AS missnum, (select max(id) from @TT)
UNION ALL
SELECT missnum + 1, maxid FROM Missing
WHERE missnum < maxid
)
SELECT missnum
FROM Missing
LEFT OUTER JOIN @TT tt on tt.id = Missing.missnum
WHERE tt.id is NULL
OPTION (MAXRECURSION 0);
【讨论】：
试试这个：
declare @min int
declare @max int
select @min = min(seq_field), @max = max(seq_field) from [Table]
create table #tmp (Field_No int)
while @min <= @max
begin
if not exists (select * from [Table] where seq_field = @min)
insert into #tmp (Field_No) values (@min)
set @min = @min + 1
end
select * from #tmp
drop table #tmp
【讨论】：
最好的解决方案是使用带有序列的临时表。假设您构建了这样一个表，带有 NULL 检查的 LEFT JOIN 应该可以完成这项工作：
SELECT #sequence.value
FROM #sequence
LEFT JOIN MyTable ON #sequence.value = MyTable.value
WHERE MyTable.value IS NULL
但是，如果您必须经常重复此操作（并且对于数据库中的 1 个序列更多），我将创建一个“静态数据”表并使用脚本将其填充到所有您需要的表格。
【讨论】：
SELECT CASE WHEN MAX(column_name) = COUNT(*)
THEN CAST(NULL AS INTEGER)
-- THEN MAX(column_name) + 1 as other option
WHEN MIN(column_name) > 1
THEN 1
WHEN MAX(column_name) <> COUNT(*)
THEN (SELECT MIN(column_name)+1
FROM table_name
WHERE (column_name+ 1)
NOT IN (SELECT column_name FROM table_name))
ELSE NULL END
FROM table_name;
【讨论】：
这是一个用于创建存储过程的脚本，该存储过程返回给定日期范围内缺少的序列号。
CREATE PROCEDURE dbo.ddc_RolledBackOrders
-- Add the parameters for the stored procedure here
@StartDate DATETIME ,
@EndDate DATETIME
AS
BEGIN
SET NOCOUNT ON;
DECLARE @Min BIGINT
DECLARE @Max BIGINT
DECLARE @i BIGINT
IF OBJECT_ID('tempdb..#TempTable') IS NOT NULL
BEGIN
DROP TABLE #TempTable
END
CREATE TABLE #TempTable
(
TempOrderNumber BIGINT
)
SELECT @Min = ( SELECT MIN(ordernumber)
FROM dbo.Orders WITH ( NOLOCK )
WHERE OrderDate BETWEEN @StartDate AND @EndDate)
SELECT @Max = ( SELECT MAX(ordernumber)
FROM dbo.Orders WITH ( NOLOCK )
WHERE OrderDate BETWEEN @StartDate AND @EndDate)
SELECT @i = @Min
WHILE @i <= @Max
BEGIN
INSERT INTO #TempTable
SELECT @i
SELECT @i = @i + 1
END
SELECT TempOrderNumber
FROM #TempTable
LEFT JOIN dbo.orders o WITH ( NOLOCK ) ON tempordernumber = o.OrderNumber
WHERE o.OrderNumber IS NULL
END
去
【讨论】：
是不是所有给定的解决方案都太复杂了？ 这不是更简单吗：
SELECT *
FROM (SELECT row_number() over(order by number) as N from master..spt_values) t
where N not in (select 1 as sequence union
select 2 union
select 3 union
select 4 union
select 5 union
select 7 union
select 10 union
select 15
)
【讨论】：
这是我对这个问题的解释，将内容放在我可以在脚本的其余部分轻松访问的 Table 变量中。
DECLARE @IDS TABLE (row int, ID int)
INSERT INTO @IDS
select ROW_NUMBER() OVER (ORDER BY x.[Referred_ID]), x.[Referred_ID] FROM
(SELECT b.[Referred_ID] + 1 [Referred_ID]
FROM [catalog].[dbo].[Referrals] b) as x
LEFT JOIN [catalog].[dbo].[Referrals] a ON x.[Referred_ID] = a.[Referred_ID]
WHERE a.[Referred_ID] IS NULL
select * from @IDS
【讨论】：
只是为了好玩，我决定发布我的解决方案。
我的表中有一个身份列，我想找到丢失的发票号码。
我查看了所有我能找到的示例，但它们不够优雅。
CREATE VIEW EENSkippedInvoicveNo
AS
SELECT CASE WHEN MSCNT = 1 THEN CAST(MSFIRST AS VARCHAR (8)) ELSE
CAST(MSFIRST AS VARCHAR (8)) + ' - ' + CAST(MSlAST AS VARCHAR (8)) END AS MISSING,
MSCNT, INV_DT FROM (
select invNo+1 as Msfirst, inv_no -1 as Mslast, inv_no - invno -1 as msCnt, dbo.fmtdt(Inv_dt) AS INV_dT
from (select inv_no as invNo, a4glidentity + 1 as a4glid
from oehdrhst_sql where inv_dt > 20140401) as s
inner Join oehdrhst_sql as h
on a4glid = a4glidentity
where inv_no - invno <> 1
) AS SS
【讨论】：
DECLARE @MaxID INT = (SELECT MAX(timerecordid) FROM dbo.TimeRecord)
SELECT SeqID AS MissingSeqID
FROM (SELECT ROW_NUMBER() OVER (ORDER BY column_id) SeqID from sys.columns) LkUp
LEFT JOIN dbo.TimeRecord t ON t.timeRecordId = LkUp.SeqID
WHERE t.timeRecordId is null and SeqID < @MaxID
我在这里找到了这个答案： http://sql-developers.blogspot.com/2012/10/how-to-find-missing-identitysequence.html
我一直在寻找解决方案并找到了很多答案。这是我用过的，效果很好。我希望这可以帮助任何寻找类似答案的人。
【讨论】：
-- This will return better Results
-- ----------------------------------
;With CTERange
As (
select (select isnull(max(ArchiveID)+1,1) from tblArchives where ArchiveID < md.ArchiveID) as [from],
md.ArchiveID - 1 as [to]
from tblArchives md
where md.ArchiveID != 1 and not exists (
select 1 from tblArchives md2 where md2.ArchiveID = md.ArchiveID - 1)
) SELECT [from], [to], ([to]-[from])+1 [total missing]
From CTERange
ORDER BY ([to]-[from])+1 DESC;
from to total missing
------- ------- --------------
6 6 1
8 8 1
11 14 4
【讨论】：
DECLARE @TempSujith TABLE
(MissingId int)
Declare @Id Int
DECLARE @mycur CURSOR
SET @mycur = CURSOR FOR Select Id From tbl_Table
OPEN @mycur
FETCH NEXT FROM @mycur INTO @Id
Declare @index int
Set @index = 1
WHILE @@FETCH_STATUS = 0
BEGIN
if (@index < @Id)
begin
while @index < @Id
begin
insert into @TempSujith values (@index)
set @index = @index + 1
end
end
set @index = @index + 1
FETCH NEXT FROM @mycur INTO @Id
END
Select Id from tbl_Table
select MissingId from @TempSujith
【讨论】：
创建一个有用的Tally table：
-- can go up to 4 million or 2^22
select top 100000 identity(int, 1, 1) Id
into Tally
from master..spt_values
cross join master..spt_values
将其编入索引，或将该单列设为 PK。 然后使用 EXCEPT 来获取您丢失的号码。
select Id from Tally where Id <= (select max(Id) from TestTable)
except
select Id from TestTable
【讨论】：
您也可以使用 CTE 之类的东西来生成完整序列：
创建表#tmp(sequence int) 插入 #tmp(sequence) 值 (1) 插入 #tmp(sequence) 值 (2) 插入 #tmp(sequence) 值 (3) 插入 #tmp(sequence) 值 (5) 插入 #tmp(sequence) 值 (6) 插入 #tmp(sequence) 值 (8) 插入 #tmp(sequence) 值 (10) 插入 #tmp(sequence) 值 (11) 插入 #tmp(sequence) 值 (14) DECLARE @max INT
SELECT @max = max(sequence) from #tmp;
with full_sequence
(
Sequence
)
as
(
SELECT 1 Sequence
UNION ALL
SELECT Sequence + 1
FROM full_sequence
WHERE Sequence < @max
)
SELECT
full_sequence.sequence
FROM
full_sequence
LEFT JOIN
#tmp
ON
full_sequence.sequence = #tmp.sequence
WHERE
#tmp.sequence IS NULL
嗯 - 由于某种原因，格式在这里不起作用？谁能看出问题？
【讨论】：
我制作了一个 proc，因此您可以发送表名和密钥，结果是给定表中缺失数字的列表
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
create PROCEDURE [dbo].[action_FindMissing_Autoincremnt]
(
@tblname as nvarchar(50),
@tblKey as nvarchar(50)
)
AS
BEGIN
SET NOCOUNT ON;
declare @qry nvarchar(4000)
set @qry = 'declare @min int '
set @qry = @qry + 'declare @max int '
set @qry = @qry +'select @min = min(' + @tblKey + ')'
set @qry = @qry + ', @max = max('+ @tblKey +') '
set @qry = @qry + ' from '+ @tblname
set @qry = @qry + ' create table #tmp (Field_No int)
while @min <= @max
begin
if not exists (select * from '+ @tblname +' where '+ @tblKey +' = @min)
insert into #tmp (Field_No) values (@min)
set @min = @min + 1
end
select * from #tmp order by Field_No
drop table #tmp '
exec sp_executesql @qry
END
GO
【讨论】：
SELECT TOP 1 (Id + 1)
FROM CustomerNumberGenerator
WHERE (Id + 1) NOT IN ( SELECT Id FROM CustomerNumberGenerator )
为我的公司开发客户编号生成器。不是最有效的，但绝对是最易读的
该表有一个 Id 列。 该表允许通过用户关闭序列手动插入 Id。 该方案解决了用户决定选择高数的情况
【讨论】：