使用 Smopy 的 Matplotlib 动画中的额外图形

Question

我正在尝试在 jupyter 中使用 smopy 和 matplotlib 创建动画地图，但是当我运行代码时，我得到两个数字而不是一个。第一个图显示在地图上方并且为空。谁能告诉我如何解决这个问题，以便只绘制动画？

import smopy
import matplotlib.animation as animation

n= 1000
%matplotlib notebook

def update(curr):
    if curr == n-100:
        a.event_source.stop()
    lons = crime_df.X[curr:curr+100]
    lats = crime_df.Y[curr:curr+100]
    x,y = map.to_pixels(lats,lons)
    ax.scatter(x, y, c='r', alpha=0.7, s=200)
    plt.title(curr)

fig = plt.figure()
ax = smopy.Map((37.6624,-122.5168,37.8231,-122.3589), z=12)
ax = ax.show_mpl(figsize=(8,8))
a = animation.FuncAnimation(fig, update, interval=100)

Answer 1

您不应该创建一个额外的数字，如果这是不希望的：忽略plt.figure()。

import smopy
import matplotlib.pyplot as plt
import matplotlib.animation as animation

n= 1000
%matplotlib notebook

def update(curr):
    if curr == n-100:
        a.event_source.stop()
    lons = crime_df.X[curr:curr+100]
    lats = crime_df.Y[curr:curr+100]
    x,y = map.to_pixels(lats,lons)
    ax.scatter(x, y, c='r', alpha=0.7, s=200)
    plt.title(curr)


m = smopy.Map((37.6624,-122.5168,37.8231,-122.3589), z=12)
ax = m.show_mpl(figsize=(8,8))
a = animation.FuncAnimation(ax.figure, update, interval=100)

或者预先创建图形，

fig, ax = plt.subplots(figsize=(8,8))
m = smopy.Map((37.6624,-122.5168,37.8231,-122.3589), z=12)
m.show_mpl(ax = ax)
a = animation.FuncAnimation(fig, update, interval=100)