Java 方法创建即使工作正常也无法读取

Question

我想创建一个方法，我可以简单地从 Swing 表单中的文本字段中获取文本。然而，试图让它被我的“if 语句”之一识别最终会出现一个错误，告诉我它无法找到该符号，尽管它已被定义。我还想创建更简洁的代码，因为我这样做的方式似乎相当重复和混乱；有没有办法缩短重复次数并将它们也称为变量？

    public class TextGrabber {
    int [] grabText = {Integer.parseInt(DigitValue.getText())};
    }    

int digit1 = TextGrabber;
    if (digit1 == 1) {
        Digi1.setVisible(false);
        Digi2.setVisible(false);
        Digi3.setVisible(true);
        Digi4.setVisible(false); //This textfield will be hidden
        Digi5.setVisible(false);
        Digi6.setVisible(true);
        Digi7.setVisible(false);
    }

    int digit2 = Integer.parseInt(DigitValue.getText());
    if (digit2 == 2) {
        Digi1.setVisible(true);
        Digi2.setVisible(false);
        Digi3.setVisible(true);
        Digi4.setVisible(true); //This textfield will be hidden
        Digi5.setVisible(true);
        Digi6.setVisible(false);
        Digi7.setVisible(true);
    }

    int digit3 = Integer.parseInt(DigitValue.getText());
    if (digit3 == 3) {
        Digi1.setVisible(true);
        Digi2.setVisible(false);
        Digi3.setVisible(true);
        Digi4.setVisible(true); //This textfield will be hidden
        Digi5.setVisible(false);
        Digi6.setVisible(true);
        Digi7.setVisible(true);
    }

    int digit4 = Integer.parseInt(DigitValue.getText());
    if (digit4 == 4) {
        Digi1.setVisible(false);
        Digi2.setVisible(true);
        Digi3.setVisible(true);
        Digi4.setVisible(true); //This textfield will be hidden
        Digi5.setVisible(false);
        Digi6.setVisible(true);
        Digi7.setVisible(false);
    }

    int digit5 = Integer.parseInt(DigitValue.getText());
    if (digit5 == 5) {
        Digi1.setVisible(true);
        Digi2.setVisible(true);
        Digi3.setVisible(false);
        Digi4.setVisible(true); //This textfield will be hidden
        Digi5.setVisible(false);
        Digi6.setVisible(true);
        Digi7.setVisible(true);
    }

    int digit6 = Integer.parseInt(DigitValue.getText());
    if (digit6 == 6) {
        Digi1.setVisible(true);
        Digi2.setVisible(true);
        Digi3.setVisible(false);
        Digi4.setVisible(true); //This textfield will be hidden
        Digi5.setVisible(true);
        Digi6.setVisible(true);
        Digi7.setVisible(true);
    }

    int digit7 = Integer.parseInt(DigitValue.getText());
    if (digit7 == 7) {
        Digi1.setVisible(true);
        Digi2.setVisible(false);
        Digi3.setVisible(true);
        Digi4.setVisible(true); //This textfield will be hidden
        Digi5.setVisible(false);
        Digi6.setVisible(true);
        Digi7.setVisible(false);
    }

    int digit8 = Integer.parseInt(DigitValue.getText());
    if (digit8 == 8) {
        Digi1.setVisible(true);
        Digi2.setVisible(true);
        Digi3.setVisible(true);
        Digi4.setVisible(true); //This textfield will be hidden
        Digi5.setVisible(true);
        Digi6.setVisible(true);
        Digi7.setVisible(true);
    }

    int digit9 = Integer.parseInt(DigitValue.getText());
    if (digit9 == 9) {
        Digi1.setVisible(true);
        Digi2.setVisible(true);
        Digi3.setVisible(true);
        Digi4.setVisible(true); //This textfield will be hidden
        Digi5.setVisible(false);
        Digi6.setVisible(true);
        Digi7.setVisible(true);
    }
}                                         

private void jButton1ActionPerformed(java.awt.event.ActionEvent evt)      {                                         
    // TODO add your handling code here:

    int AddOneDigit = Integer.parseInt(DigitValue.getText());
    AddOneDigit = AddOneDigit + 1;
    String NewSet = Integer.toString (AddOneDigit);
    DigitValue.setText(NewSet);        
    ShowDigitActionPerformed(evt);

    int check = Integer.parseInt(DigitValue.getText());
    if (check >= 10) {
        check = 0;
        String CheckS = Integer.toString (check);
        DigitValue.setText(CheckS);
        Digi1.setVisible(true);
        Digi2.setVisible(true);
        Digi3.setVisible(true);
        Digi4.setVisible(false); //This textfield will be hidden
        Digi5.setVisible(true);
        Digi6.setVisible(true);
        Digi7.setVisible(true);     
}                              

Answer 1

将掩码存储为数组，然后用类似的东西构建它

int digit = Integer.parseInt(DigitValue.getText());
boolean[][] mask = { { false, false, true, false, false, true, false },
        { true, false, true, true, true, false, true },
        { true, false, true, true, false, true, true },
        { false, true, true, true, false, true, false },
        { true, true, false, true, false, true, true },
        { true, true, false, true, true, true, true },
        { true, false, true, true, false, true, false },
        { true, true, true, true, true, true, true },
        { true, true, true, true, false, true, true } };
boolean[] digits = mask[digit - 1];
Digi1.setVisible(digits[0]);
Digi2.setVisible(digits[1]);
Digi3.setVisible(digits[2]);
Digi4.setVisible(digits[3]);
Digi5.setVisible(digits[4]);
Digi6.setVisible(digits[5]);
Digi7.setVisible(digits[6]);

我还注意到您没有数字 '0' 的映射。

Answer 2

我不确定这是否会对您有很大帮助，但您也许可以通过创建一个方法来清理您的一些代码。您可以创建一个方法来声明“Digi”的可见性。像这样的方法可能类似于下面的代码。

代码：

public void multipleVisibleSet(boolean 1Visible, boolean 2Visible, boolean 3Visible, 
              boolean 4Visible, boolean 5Visible, boolean 6Visible, boolean 7Visible){
  Digi1.setVisible(1Visible);                                 //Add as many as you need
  Digi2.setVisible(2Visible);
  Digi3.setVisible(3Visible);
  Digi4.setVisible(4Visible);
  Digi5.setVisible(5Visible);
  Digi6.setVisible(6Visible);
  Digi7.setVisible(7isible);
}