Room Kotlin 找不到字段的设置器答案

【问题标题】：Room Kotlin Cannot find setter for fieldRoom Kotlin 找不到字段的设置器
【发布时间】：2018-07-25 20:49:32
【问题描述】：

您好，我正在尝试在基于 MVP 的项目中使用带有 Kotlin 的 Room。

我的问题是，当我创建一个数据类和相关的 DAO 时，所有类都会成功生成，但是当创建第二个数据类并且它是 DAO 时，Error:Cannot find setter for field. 会抛出在 android studio 中重建命令

@Entity(tableName = "TB_CLASSES")
class TbClass(
@ColumnInfo(name = "ID")
@PrimaryKey(autoGenerate = true)  var id: Int =-1,
@ColumnInfo(name = "NAME") var name: String="",
@ColumnInfo(name = "CAPTION") var caption: String="",
@ColumnInfo(name = "TYPE") var type: String="")

@Entity(tableName = "TB_FEATURE_DISA")
class TbFeatureDisa(
@ColumnInfo(name = "ID")
@PrimaryKey(autoGenerate = true) var id: Int=-1,
@ColumnInfo(name = "FEATURE_ID") var featureId: Int=-1,
@ColumnInfo(name = "DISA_ID") var disaId: Int=-1,
@ColumnInfo(name = "IS_SOLVED") var isSolved: Int=-1,
@ColumnInfo(name = "DISA_LEVEL") var disaLevel: Double=-0.1,
@ColumnInfo(name = "RESOLVER_USER_NAME") var resolverUserName: String="",
@ColumnInfo(name = "RESOLVE_TIME") var resolveTime: Date? =null,
@ColumnInfo(name = "REPORT_VIST_ID") var reportVisitId: Int=-1,
@ColumnInfo(name = "REPORT_FAULT_ID") var reportFaultId: Int=-1,
@ColumnInfo(name = "SOLVE_VIST_ID") var solveVisitId: Int=-1,
@ColumnInfo(name = "SOLVE_SERVICE_ID") var solveServiceId: Int=-1,
@ColumnInfo(name = "SOLVE_FUALT_ID") var solveFaultId: Int=-1)

我也检查了这个link 和这个link，但没有一个对我有用

【问题讨论】：

标签： android kotlin android-room

【解决方案1】：

我终于找到了解决办法。问题与属性命名有关。

以下导致编译时出错：

 @ColumnInfo(name = "IS_SOLVED") var isSolved

但是当我把上面的改成下面的时候，错误就解决了：

 @ColumnInfo(name = "IS_SOLVED") var solved

我们不能使用 SQLite 保留关键字line 进行字段命名。我使用的是 Room 1.0.0 版和 kotlin 1.1.51 版。

【讨论】：

【解决方案2】：

创建一个data class，它将为属性提供setters 和getters，如

@Entity(tableName = "TB_CLASSES")
data class TbClass( //< add data prior to class
@ColumnInfo(name = "ID")
@PrimaryKey(autoGenerate = true)  var id: Int =-1,
@ColumnInfo(name = "NAME") var name: String="",
@ColumnInfo(name = "CAPTION") var caption: String="",
@ColumnInfo(name = "TYPE") var type: String="")

TbFeatureDisa

    @Entity(tableName = "TB_FEATURE_DISA")
    data class TbFeatureDisa(
    @ColumnInfo(name = "ID")
    @PrimaryKey(autoGenerate = true) var id: Int=-1,
    @ColumnInfo(name = "FEATURE_ID") var featureId: Int=-1,
    @ColumnInfo(name = "DISA_ID") var disaId: Int=-1,
    @ColumnInfo(name = "IS_SOLVED") var isSolved: Int=-1,
    @ColumnInfo(name = "DISA_LEVEL") var disaLevel: Double=-0.1,
    @ColumnInfo(name = "RESOLVER_USER_NAME") var resolverUserName: String="",
    @ColumnInfo(name = "RESOLVE_TIME") var resolveTime: Date? =null,
    @ColumnInfo(name = "REPORT_VIST_ID") var reportVisitId: Int=-1,
    @ColumnInfo(name = "REPORT_FAULT_ID") var reportFaultId: Int=-1,
    @ColumnInfo(name = "SOLVE_VIST_ID") var solveVisitId: Int=-1,
    @ColumnInfo(name = "SOLVE_SERVICE_ID") var solveServiceId: Int=-1,
    @ColumnInfo(name = "SOLVE_FUALT_ID") var solveFaultId: Int=-1)

【讨论】：

【解决方案3】：

对于像我这样缺乏关注并通过 Google 偶然发现这里的人，使用 val 而不是 var 会给出相同的错误消息。

【讨论】：