如何以不同于 10 的基数数到 100（java 程序）

Question

import java.util.Scanner;
public class Problem5 {
    public static void main(String args[]) {
    System.out.println("Base Calculator");
    System.out.println("Input a number greater than 0 and less than 10 to use as your base");
    System.out.println("------------------------------------------------------------------");
    System.out.println("Base: ");
    //menu
    Scanner input = new Scanner(System.in);
    int base = 0;
    int basenumber[];
    basenumber = new int[1000001];
    base = input.nextInt();
    int remainder, tens;

    if (base <= 0 || base >=10) { //only working with this parameter
        System.out.println("This calculator does not work with bases that are less than 1 or bases that are greater than 9. Please re-run the program.");
        return;
    }
    else {
        System.out.print("(This means a base " + base + " calculator. Hence, the allowed values corresponding to base 10 values of 0 through 102 would be: ");
        for(int i = 0; i<=101; i++) { //a sample of what i am getting when a base is inputed;notice how when the number gets to 40 base 4, it does not go automatically to 100
            if(i < base){
                basenumber[i] = i;
                System.out.print(basenumber[i] + ", ");
            }
            if (i >= base && i < 101){
                tens = (i / base) * 10;
                remainder = i % base;
                basenumber[i] = tens + remainder;
                System.out.print(basenumber[i] + ", ");
            }
            if (i >= base && i == 101){
                tens = (i / base) * 10;
                remainder = i % base;
                basenumber[i] = tens + remainder;
                System.out.println(basenumber[i] + ")");
                System.out.println("\n");
            }
        }
        //How could I change the above code to make it such that when four 4's show up in the base 4 fours spot (base 10 tens spot), it sees that as one 16 and moves it to the base 4 sixteens spot (base 10 hundreds spot)?
    }
}
}

输出

基础计算器 输入一个大于 0 且小于 10 的数字作为基数

---

基础： 4 （这意味着一个以 4 为底的计算器。因此，对应于 0 到 102 的以 10 为底的值的允许值将是：0、1、2、3、10、11、12、13、20、21、22、23、30 , 31, 32, 33, 40, 41, 42, 43, 50, 51, 52, 53, 60, 61, 62, 63, 70, 71, 72, 73, 80, 81, 82, 83, 90, 91 , 92, 93, 100, 101, 102, 103, 110, 111, 112, 113, 120, 121, 122, 123, 130, 131, 132, 133, 140, 141, 142, 143, 150, 151, 152 , 153, 160, 161, 162, 163, 170, 171, 172, 173, 180, 181, 182, 183, 190, 191, 192, 193, 200, 201, 202, 203, 210, 211, 212, 213 , 220, 221, 222, 223, 230, 231, 232, 233, 240, 241, 242, 243, 250, 251

预期的输出是： 0,1,2,3,10,......,33,100,101,102,103,110（基数 4）

如何修改上面的代码以产生预期的输出？

Answer 1

如果不需要，就不要重新发明*……

for (int i=0; i<101; i++)
{
      System.out.print(Integer.toString(i, base));
      if (i!=100)
      {
        System.out.print(", ");
      }
}

Answer 2

如果您决定不使用Integer.toString(value, base)，则此实现是一个示例：

public class Problem5 {

    public static int convertToBaseNumber(int base10num, int base){
       int highestBase = (int) Math.floor(Math.log(base10num)/Math.log(base));
       int currentBase = highestBase;
       int remainder = base10num;
       int output = 0;
       while(currentBase >= 0){

            int divisor = (int) Math.pow(base,currentBase);

            int num = ((int) Math.floor(remainder/divisor));
            output = output + (int)(num * Math.pow(10,currentBase));

            remainder = remainder%divisor;

            currentBase--;
       }

       return output;
    }

    public static void main(String args[]) {
        System.out.println("Base Calculator");
        System.out.println("Input a number greater than 0 and less than 10 to use as your base");
        System.out.println("------------------------------------------------------------------");
        System.out.println("Base: ");
        //menu
        Scanner input = new Scanner(System.in);
        int base = input.nextInt();

        if (base <= 0 || base >=10) { 
            System.out.println("This calculator does not work with bases that are less than 1 or bases that are greater than 9. Please re-run the program.");
            return;
        }
        else {
            System.out.println("(This means a base " + base + " calculator. Hence, the allowed values corresponding to base 10 values of 0 through 102 would be: ");
            for(int i = 0; i <= 102; i++) {
                System.out.print(Problem5.convertToBaseNumber(i, base) + ", ");
            }
            System.out.println("\n");
        }
    }
}