【发布时间】:2019-08-27 09:02:33
【问题描述】:
我正在使用带有System.Windows.Forms 的 PowerShell 制作一个简单的 GUI 表单。
对于每个文本框-按钮对,我希望按钮打开文件浏览器,一旦选择了文件,文件路径应该写在相应的文本框中。
在下面的代码中,New-TextBox 创建一个标签和一个文本框,New-Button 创建一个按钮。
使用这些函数可以创建带有 3 个按钮的 3 个文本框。
然后我创建了函数Set-FileDialogButton。它需要一个按钮和文本框作为参数,并且应该创建一个打开文件浏览器的按钮单击事件,获取选定的文件路径并将其从参数写入文本框。
点击事件和文件浏览器有效。但是,选择文件后,我得到了
The property 'Text' cannot be found on this object. Verify that the property exists and can b
e set.
At D:\...\test.ps1:62 char:5
+ $inputTextBox.Text = $FileBrowser.FileName
+ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
+ CategoryInfo : InvalidOperation: (:) [], RuntimeException
+ FullyQualifiedErrorId : PropertyNotFound
所以我假设在函数中传递文本框时我做错了。如果我不将点击事件包装在一个函数中,我的代码就可以正常工作。
代码:
Add-Type -assembly System.Windows.Forms
$main_form = New-Object System.Windows.Forms.Form
$main_form.Text ='AP209 Converter GUI'
$main_form.Width = 300
$main_form.Height = 200
$main_form.AutoSize = $true
#Creates a label and text box:
function New-TextBox($labelText, $x, $y, $w){
$label = New-Object System.Windows.Forms.Label
$label.Text = $labelText
$label.Location = New-Object System.Drawing.Point($x, $y)
$label.AutoSize = $true
$main_form.Controls.Add($label)
$textbox = New-Object system.Windows.Forms.TextBox
$textbox.multiline = $false
$textbox.width = $w
$textbox.height = 20
$textbox.location = New-Object System.Drawing.Point(($x + 50), $y)
$main_form.Controls.Add($textbox)
return $textbox
}
#Creates a button with $text as label:
function New-Button($text, $x, $y, $w, $h){
$button = New-Object System.Windows.Forms.Button
$button.Location = New-Object System.Drawing.Size($x, $y)
$button.Size = New-Object System.Drawing.Size($w, $h)
$button.Text = $text
$main_form.Controls.Add($button)
return $button
}
$textBoxW = 100
$labelX = 0
$buttonX = $x + 155
$y = 10
$dy = 30
$buttonW = 25
$buttonH = 20
#Create 3 text boxes and buttons:
$textbox1 = New-TextBox "File 1" $labelX $y $textBoxW
$button1 = New-Button "..." $buttonX $y $buttonW $buttonH
$y = $y + $dy
$textbox2 = New-TextBox "File 2" $labelX $y $textBoxW
$button2 = New-Button "..." $buttonX $y $buttonW $buttonH
$y = $y + $dy
$textbox3 = New-TextBox "File 3" $labelX $y $textBoxW
$button3 = New-Button "..." $buttonX $y $buttonW $buttonH
#Set click event to button:
function Set-FileDialogButton($button, $inputTextBox){
$button.Add_Click(
{
$FileBrowser = New-Object System.Windows.Forms.OpenFileDialog -Property @{ InitialDirectory = $loadpath}
$fileBrowserReturned = $FileBrowser.ShowDialog()
if($fileBrowserReturned -eq "OK"){
$inputTextBox.Text = $FileBrowser.FileName
$inputTextBox.SelectionStart = $inputTextBox.Text.Length;
}
}
)
}
Set-FileDialogButton $button1 $textbox1
Set-FileDialogButton $button2 $textbox2
Set-FileDialogButton $button3 $textbox3
$main_form.ShowDialog()
【问题讨论】:
-
如果您只在 AddClick 事件中分别处理每个文件浏览按钮,您的代码会更容易且更具可读性。
-
@Scepticalist 这个想法是通过将 AddClick 包装在一个函数中来删除重复代码,并使其更具可读性...
标签: winforms powershell