Proguard中的* vs ** vs ***？答案

【问题标题】：* vs ** vs *** in Proguard?Proguard中的* vs ** vs ***？
【发布时间】：2013-11-12 07:10:28
【问题描述】：

Proguard 中的*、** 和*** 通配符有什么区别？例如：

-keep class com.mypackage.*

对

-keep class com.mypackage.**

对

-keep class com.mypackage.***

【问题讨论】：

标签： android proguard

【解决方案1】：

*   matches any part of a method name. OR matches any part of a class name not containing the package separator.
**  matches any part of a class name, possibly containing any number of package separators.
*** matches any type (primitive or non-primitive, array or non-array).

注意* 和** 通配符永远不会匹配原始类型。此外，只有 * 通配符可以匹配任意维度的数组类型。例如，“ get*()”匹配"java.lang.Object getObject()"，但不匹配"float getFloat()"，也不匹配"java.lang.Object[] getObjects()"。

【讨论】：

这个答案对应的文档在guardsquare.com/en/products/proguard/manual/…

【解决方案2】：

*   matches any part of a filename not containing the directory separator.
**  matches any part of a filename, possibly containing any number of directory separators.

【讨论】：

【解决方案3】：

来自the document：

*   matches any part of a class name not containing the package separator. For example, "com.example.*Test*" matches "com.example.Test" and "com.example.YourTestApplication", but not "com.example.mysubpackage.MyTest". Or, more generally, "com.example.*" matches all classes in "com.example", but not in its subpackages.
**   matches any part of a class name, possibly containing any number of package separators. For example, "**.Test" matches all Test classes in all packages except the root package. Or, "com.example.**" matches all classes in "com.example" and in its subpackages.
***   matches any type (primitive or non-primitive, array or non-array).

【讨论】：