Unity Google Play 游戏创建游戏有邀请问题

Question

我可以创建带有邀请的游戏，我可以邀请和接受邀请，这一切都很好。当我为 3 人或更多人制作游戏时出现此问题：

• 用户 A 创建 3 人或至少 2 人的游戏
• 用户 A 选择邀请某人，然后添加另一个人来自动选择房间
• 用户 A 邀请用户 B
• 用户 B 接受
• 他们都等到“立即开始”按钮出现
• 用户 B 按下立即开始按钮，由于某种原因 OnRoomConnected() 被调用了 3 次，游戏没有开始（据我所知，房间也从未离开过，因为该用户无法接收邀请不再）
• 从用户 A 的角度来看没有任何变化，他仍在等待游戏开始或搜索另一个自动选择对手

我确定问题不在于我的代码。我创建了一个单独的简单项目，仅用于测试目的，它做的事情完全相同。所以我开始认为这可能不是我的问题，我在互联网上没有看到类似的问题。所以我决定在这里问。我该怎么办？可能是什么问题？

基本上就是这样。即使我将玩家数量限制为 3 或 4（最小和最大玩家数量相等，3 或 4），它仍然让我过早地开始游戏，并且我在多次调用 OnRoomConnected() 时遇到同样的问题并且游戏没有开始。

提前致谢。如果您有链接或可以帮助我解决此问题的内容，将不胜感激。

这是我用于登录游戏和创建房间的基本代码。

public class GPGM : MonoBehaviour, RealTimeMultiplayerListener{

public static GPGM instance;
public static int target;

private void Awake()
{
    target = 60;
    QualitySettings.vSyncCount = 0;
    Application.targetFrameRate = target;

    if (instance == null)
    {
        DontDestroyOnLoad(gameObject);
        instance = this;
    }
    else if (instance != this)
    {
        Destroy(gameObject);
    }
}
// Use this for initialization
void Start () {
    Login();
}

// Update is called once per frame
void Update () {

}

public void Login()
{
    StartCoroutine(checkInternetConnection((isConnected) =>
    {
        LoginGPG();
    }));
}

IEnumerator checkInternetConnection(Action<bool> action)
{
    WWW www;
    www = new WWW("http://google.com");

    yield return www;

    if (!String.IsNullOrEmpty(www.error))
    {
        Debug.Log("DebugM | no internet connection");
        action(false);
    }
    else
    {
        Debug.Log("DebugM | There IS connection");
        action(true);
    }
}

public void LoginGPG()
{
    PlayGamesClientConfiguration config = new PlayGamesClientConfiguration.Builder().WithInvitationDelegate(OnInvitationReceived).Build();
    PlayGamesPlatform.InitializeInstance(config);
    PlayGamesPlatform.DebugLogEnabled = true;
    PlayGamesPlatform.Activate();
    Debug.Log("DebugM | LoginGPG");
    Auth();

}

public void Auth()
{
    Debug.Log("DebugM | Auth");
    try
    {
        //doesn't work sometimes for some reason. It gives null data if success is false
        //reason for false success is unknown
        Social.localUser.Authenticate((bool succes) =>
        {
            if (succes)
            {
                Debug.Log("DebugM | Logged in");
            }else
            {
                Debug.Log("DebugM | authentication failed");
            }
        });
    }
    catch (Exception e)
    {
        Debug.Log("DebugM | Auth() has failed with error: " + e.Message);
    }
}

public void OnInvitationReceived(Invitation invitation, bool shouldAutoAccept)
{
    StartCoroutine(InvitationCo(invitation, shouldAutoAccept));
}

Invitation mIncomingInvitation;
IEnumerator InvitationCo(Invitation invitation, bool shouldAutoAccept)
{
    yield return new WaitUntil(() => SceneManager.GetActiveScene().name == "Lobby");

    Debug.Log("DebugM | Invitation has been received!!!");
    //StartCoroutine(LM.LoadingAnim());
    if (shouldAutoAccept)
    {
        Debug.Log("DebugM | Should auto accept: TRUE");
        PlayGamesPlatform.Instance.RealTime.AcceptInvitation(invitation.InvitationId, instance);

    }
    else
    {
        // The user has not yet indicated that they want to accept this invitation.
        // We should *not* automatically accept it. Rather we store it and 
        // display an in-game popup:
        Debug.Log("DebugM | Should auto accept: FALSE");
        Lobby LM = FindObjectOfType<Lobby>();
        LM.invPanel.SetActive(true);
        mIncomingInvitation = invitation;
    }
}

public void AcceptGoogleInv(GameObject panel)
{
    if (mIncomingInvitation != null)
    {
        // show the popup
        //string who = (mIncomingInvitation.Inviter != null &&
        //    mIncomingInvitation.Inviter.DisplayName != null) ?
        //        mIncomingInvitation.Inviter.DisplayName : "Someone";
        Debug.Log("DebugM | Invitation has been accepted");
        PlayGamesPlatform.Instance.RealTime.AcceptInvitation(mIncomingInvitation.InvitationId, instance);
        panel.SetActive(false);
    }
}

public void CreateQuickRoom()
{
                PlayGamesPlatform.Instance.RealTime.CreateWithInvitationScreen(1, 3, 1, instance );
}

public void OnRoomSetupProgress(float percent)
{
    Debug.Log("OnRoomSetupProgress()");
    PlayGamesPlatform.Instance.RealTime.ShowWaitingRoomUI();
}

public void OnRoomConnected(bool success)
{
    SceneManager.LoadScene("Game");
    Debug.Log("DebugM | Room conected");
}

public void OnLeftRoom()
{
    throw new NotImplementedException();
}

public void OnParticipantLeft(Participant participant)
{
    throw new NotImplementedException();
}

public void OnPeersConnected(string[] participantIds)
{
    throw new NotImplementedException();
}

public void OnPeersDisconnected(string[] participantIds)
{
    throw new NotImplementedException();
}

public void OnRealTimeMessageReceived(bool isReliable, string senderId, byte[] data)
{
    throw new NotImplementedException();
}}

编辑（图片）： This is when I wait for the last auto pick slot to fill (it works like this only when people were invited to the game)

The game goes to lobby for the person who pressed start and the others still wait for the last autopick even if 1 player practically left the room

Answer 1

你可以这样做：

public void OnRoomConnected (bool success)
   {
     if (success)
      {
        //Start the game here
        SceneManager.LoadScene("Game");
        Debug.Log("DebugM | Room conected");
      }
     else
      {
        //Do somthing else.
      }
   }

或通过检查已连接的参与者数量来做到这一点的最佳方法。

public void OnPeersConnected (string[] participantIds)
    {
      List<Participant> playerscount = PlayGamesPlatform.Instance.RealTime.GetConnectedParticipants();
      if (playerscount != null && playerscount.Count > 1)//this condition should be decided by you.
        {
          //Start the game here
          SceneManager.LoadScene("Game");
        }
    }