替换javascript中的所有大括号字符串

Question

我想做这个：

i went to the [open shops], but the [open shops] were closed

看起来像这样：

i went to the markets, but the markets were closed

用javascript替换

我对正则表达式不太好，方括号需要分隔我确定

Answer 1

试试这个：

"i went to the [open shops], but the [open shops] were closed".replace(/\[open shops\]/g, 'markets');

棘手的部分是需要转义括号并添加全局匹配以替换每个匹配的实例。欲了解更多信息：https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/replace

Answer 2

您需要做的就是将 \ 放在 [ 和 ] 之前，以将其视为常规字符。这样你的正则表达式就会变成\[openshops\]。

如果您有多个需要替换的东西（例如[shops] 和[state]），您可以执行以下动态创建正则表达式的操作。这样您就不必为每件事都硬编码。

var str = "I went to the [shops], but the [shops] were [state]. I hate it when the [shops] are [state].";
    var things = {
        shops: "markets",
        state: "closed"
    };
    for (thing in things) {
        var re = new RegExp("\\["+thing+"\\]", "g");
        str = str.replace(re, things[thing]);
    }
console.log(str);

注意，这样做时你需要使用两个反斜杠而不是一个。

Answer 3

如果您不想使用正则表达式。你可以使用类似的东西。

    var a = "i went to the [open shops], but the [open shops] were closed";
    var replacement = "KAPOW!";

    while(a.contains("[") && a.contains("]"))
    {
        var left = a.indexOf("[");
        var right = a.indexOf("]");

        a = a.substring(0,left) + replacement + a.substring(right+ 1);
    }

    console.log(a);