基于日期处理的Javascript JSON数据[关闭]答案

【问题标题】：Javascript JSON Data processed based on date [closed]基于日期处理的Javascript JSON数据[关闭]
【发布时间】：2023-04-02 07:30:01
【问题描述】：

我给出了下面的数组。我的问题是如何根据日期处理数据。例如：从服务获得以下响应。

[[
  {"claimNumber":"6396","itemNumber":"1","dateAssessed":"20/10/2015"},
  {"claimNumber":"2208","itemNumber":"1","dateAssessed":"20/09/2015"},
  {"claimNumber":"918","itemNumber":"1","dateAssessed":"12/09/2015"},
  {"claimNumber":"2208","itemNumber":"1","dateAssessed":"20/09/2015"},
  {"claimNumber":"2206","itemNumber":"1","dateAssessed":"20/09/2015"},
  {"claimNumber":"2205","itemNumber":"1","dateAssessed":"20/09/2015"},
  {"claimNumber":"2208","itemNumber":"1","dateAssessed":"20/09/2015"},
]]

我想根据日期处理数据如下：

2015 年 9 月 20 日

  {"claimNumber":"2208","itemNumber":"1","dateAssessed":"20/09/2015"},
  {"claimNumber":"2206","itemNumber":"1","dateAssessed":"20/09/2015"},
  {"claimNumber":"2205","itemNumber":"1","dateAssessed":"20/09/2015"},
  {"claimNumber":"2208","itemNumber":"1","dateAssessed":"20/09/2015"}

2015 年 10 月 20 日

   {"claimNumber":"6396","itemNumber":"1","dateAssessed":"20/10/2015"}

2015 年 12 月 9 日

  {"claimNumber":"918","itemNumber":"1","dateAssessed":"12/09/2015"}

【问题讨论】：

Array.prototype.filter()

标签： javascript arrays json

【解决方案1】：

为此制作一些排列功能。安排（）返回对象中的分组数据。

        var data = [[
            {"claimNumber":"6396","itemNumber":"1","dateAssessed":"20/10/2015"},
            {"claimNumber":"2208","itemNumber":"1","dateAssessed":"20/09/2015"},
            {"claimNumber":"918","itemNumber":"1","dateAssessed":"12/09/2015"},
            {"claimNumber":"2208","itemNumber":"1","dateAssessed":"20/09/2015"},
            {"claimNumber":"2206","itemNumber":"1","dateAssessed":"20/09/2015"},
            {"claimNumber":"2205","itemNumber":"1","dateAssessed":"20/09/2015"},
            {"claimNumber":"2208","itemNumber":"1","dateAssessed":"20/09/2015"},
        ]];

        function arrange(data) {
            var res = {};

            for(var i = 0, obj; obj = data[i]; i++) {

                if(!res[obj.dateAssessed]) {
                    res[obj.dateAssessed] = [];
                }

                res[obj.dateAssessed].push(obj);
            }

            return res;
        }

        /* it returns like:
            {
                12/09/2015: [{ ... }],
                20/09/2015: [{ ... }],
                20/10/2015: [{ ... }]
            }
        */
        arrange(data[0]);

【讨论】：

【解决方案2】：

好吧，我会这样做：

按日期排序数据，
创建新的空对象newData，
遍历数据数组，
- 数据 = 数据[i].date;
- 检查 newData[data] 是否存在：如果不存在，则使用 value 中的空数组创建它
- 将 data[i] 添加到 newData[data]

我没有提到类型转换等。

【讨论】：

@Reeno 真的是个新问题吗？

【解决方案3】：

你可以使用.filter

function reduceArr(x, date){
    return x[0].filter(function(elem){
        return elem.dateAssessed==date;
    });
}

console.log(reduceArr(x, "20/09/2015"));

这将返回所需对象的数组。

Working Fiddle

【讨论】：

【解决方案4】：

不清楚你的问题，但如果你想按日期分组，那么：

var arr=[
  {"claimNumber":"6396","itemNumber":"1","dateAssessed":"20/10/2015"},
  {"claimNumber":"2208","itemNumber":"1","dateAssessed":"20/09/2015"},
  {"claimNumber":"918","itemNumber":"1","dateAssessed":"12/09/2015"},
  {"claimNumber":"2208","itemNumber":"1","dateAssessed":"20/09/2015"},
  {"claimNumber":"2206","itemNumber":"1","dateAssessed":"20/09/2015"},
  {"claimNumber":"2205","itemNumber":"1","dateAssessed":"20/09/2015"},
  {"claimNumber":"2208","itemNumber":"1","dateAssessed":"20/09/2015"},
];
var newarr = {};
for(var i=0; i<arr.length;i++){
    newarr[arr[i].dateAssessed] = newarr[arr[i].dateAssessed] || [];
    newarr[arr[i].dateAssessed].push(arr[i]);
}

【讨论】：