Javascript对键值上的对象数组进行排序[重复]答案

【问题标题】：Javascript sort array of objects on key values [duplicate]Javascript对键值上的对象数组进行排序[重复]
【发布时间】：2017-09-28 10:09:59
【问题描述】：

我试图对包含状态键的对象数组进行排序，其中状态键具有 "online","offline","Busy" ，所以只是想以这样一种方式对数组进行排序，使所有“online”都出现在顶部，然后按“忙”然后“离线”

var arr = [{_id: "58e21249", name: "test2", status: "offline"},
           {_id: "58e1249", name: "test3", status: "online"},
           {_id: "58qwe49", name: "test21", status: "offline"},
           {_id: "58ed49", name: "test212", status: "online"},
           {_id: "58ee49", name: "test23", status: "offline"},
           {_id: "58xe49", name: "test12", status: "online"},
           {_id: "5849", name: "test2323", status: "busy"},
           {_id: "58er49", name: "test2121", status: "busy"}];

arr.sort(function(first, second) {
   if (second.status == "online") return 1;

 });

console.log(arr);

这只会返回我的状态：顶部的“在线”。谢谢

【问题讨论】：

注意：meta 上提到了这个问题。

标签： javascript arrays sorting

【解决方案1】：

试试这个：

var arr = [{_id: "58e21249", name: "test2", status: "offline"},
           {_id: "58e1249", name: "test3", status: "online"},
           {_id: "58qwe49", name: "test21", status: "offline"},
           {_id: "58ed49", name: "test212", status: "online"},
           {_id: "58ee49", name: "test23", status: "offline"},
           {_id: "58xe49", name: "test12", status: "online"},
           {_id: "5849", name: "test2323", status: "busy"},
           {_id: "58er49", name: "test2121", status: "busy"}];
           
 var statusOrder = ["online", "busy", "offline"];
 
 arr = arr.sort(function(a, b) { 
     return statusOrder.indexOf(a.status) - statusOrder.indexOf(b.status);
 });

 console.log(arr);

使用 ECMAScript6 甚至更短：

var arr = [{_id: "58e21249", name: "test2", status: "offline"},
           {_id: "58e1249", name: "test3", status: "online"},
           {_id: "58qwe49", name: "test21", status: "offline"},
           {_id: "58ed49", name: "test212", status: "online"},
           {_id: "58ee49", name: "test23", status: "offline"},
           {_id: "58xe49", name: "test12", status: "online"},
           {_id: "5849", name: "test2323", status: "busy"},
           {_id: "58er49", name: "test2121", status: "busy"}];
           
 var statusOrder = ["online", "busy", "offline"];
 
 arr = arr.sort((a, b) => statusOrder.indexOf(a.status) - statusOrder.indexOf(b.status));

 console.log(arr);

【讨论】：

注意：meta 上提到了这个问题。

【解决方案2】：

var statusOrder = ["online", "offline", "busy"];
arr.sort(function(first, second) {
    return statusOrder.indexOf(first.status) < statusOrder.indexOf(second.status);
});

【讨论】：

这段代码会格式化你的硬盘吗？