将二维数组（长度 9）转换为 3 x 3（9 个元素）的网格答案

【问题标题】：Convert a two dimensional array(length 9) to a Grids of 3 x 3 (9 elements)将二维数组（长度 9）转换为 3 x 3（9 个元素）的网格
【发布时间】：2019-10-06 17:14:13
【问题描述】：

我有一个二维数组，它代表下表中的一系列行值：

[
  ["5","3",".",".","7",".",".",".","."],
  ["6",".",".","1","9","5",".",".","."],
  [".","9","8",".",".",".",".","6","."],
  ["8",".",".",".","6",".",".",".","3"],
  ["4",".",".","8",".","3",".",".","1"],
  ["7",".",".",".","2",".",".",".","6"],
  [".","6",".",".",".",".","2","8","."],
  [".",".",".","4","1","9",".",".","5"],
  [".",".",".",".","8",".",".","7","9"]
]

我需要从中获取列值，我可以使用

map(list, zip(*arr))
and got this:

[
 ['5', '6', '.', '8', '4', '7', '.', '.', '.'], 
 ['3', '.', '9', '.', '.', '.', '6', '.', '.'], 
 ['.', '.', '8', '.', '.', '.', '.', '.', '.'], 
 ['.', '1', '.', '.', '8', '.', '.', '4', '.'], 
 ['7', '9', '.', '6', '.', '2', '.', '1', '8'], 
 ['.', '5', '.', '.', '3', '.', '.', '9', '.'], 
 ['.', '.', '.', '.', '.', '.', '2', '.', '.'], 
 ['.', '.', '6', '.', '.', '.', '8', '.', '7'], 
 ['.', '.', '.', '3', '1', '6', '.', '5', '9']
]

现在我需要创建一个类似的包含 3 x 3 网格元素的二维数组，输出应如下所示

[
 ['5','3','.','6','.','.','.','9','8'],
 ['.','7','.','1','9','5','.','.','.'],
 ['.','.','.','.','.','.','.','6','.'],
 ['8','.','.','4','.','.','7','.','.'],
 ['.','6','.','8','.','3','.','2','.'],
 ['.','.','3','.','.','1','.','.','6'],
 ['.','6','.','.','.','.','.','.','.'],
 ['.','.','.','4','1','9','.','8','.'],
 ['2','8','.','.','.','5','.','7','9']
]

我尝试将 3 个元素压缩在一起并迭代 3 行，但我一无所获

x = 3
for i in range(x):
  map(list, zip(*arr)[0,1,2])
  x += 3

【问题讨论】：

标签： python matrix iteration spatial

【解决方案1】：

无论如何，对于嵌套循环示例：

def get_3x3_grids(arr):
    grids = []
    for r in range(0, 9, 3):
        for c in range(0, 9, 3):
            grids_row = []
            for row in range(r, r + 3):
                grids_row += arr[row][c:c + 3]
            grids.append(grids_row)

    return grids

【讨论】：