【问题标题】:Yii2 ActiveDataProvider - Invalid argument supplied for foreach()Yii2 ActiveDataProvider - 为 foreach() 提供的参数无效
【发布时间】:2015-09-22 17:24:54
【问题描述】:

我在调用 project/index 控制器时收到 Invalid argument provided for foreach() 错误。似乎是什么问题?

这是模型中的搜索:

 public function search($params)
    {
        $query = Projects::find();

        // add conditions that should always apply here

        $dataProvider = new ActiveDataProvider([
            'query' => $query,
        ]);

        $this->load($params);

        if (!$this->validate()) {
            // uncomment the following line if you do not want to return any records when validation fails
            // $query->where('0=1');
            return $dataProvider;
        }

        // grid filtering conditions
        $query->andFilterWhere([
            'id' => $this->id,
            'created_at' => $this->created_at,
            'updated_at' => $this->updated_at,
        ]);

        $query->andFilterWhere(['like', 'name', $this->name])
            ->andFilterWhere(['like', 'description', $this->description]);

        return $dataProvider;

控制器:

public function actionIndex()
    {
        $searchModel  = new ProjectsQuery();
        $dataProvider = $searchModel->search(Yii::$app->request->queryParams);

        return $this->render('index', [
            'searchModel'  => $searchModel,
            'dataProvider' => $dataProvider,
        ]);
    }

查看文件:

<div class="projects-index">

    <h1><?= Html::encode($this->title) ?></h1>
    <?php echo $this->render('_search', ['model' => $searchModel]); ?>

    <p>
        <?= Html::a('Create Projects', ['create'], ['class' => 'btn btn-success']) ?>
    </p>

    <?= GridView::widget([
        'dataProvider' => $dataProvider,
        'filterModel' => $searchModel,
        'filterPosition' => 'header',
        'columns' => [
            ['class' => 'yii\grid\SerialColumn'],

            'name',
            'description:ntext',
            'created_at:date',
            'updated_at:date',

            ['class' => 'yii\grid\ActionColumn'],
        ],
    ]); ?>

</div>

【问题讨论】:

  • 你命名的 ProjectQuery yii2 通常命名为 ProjectSearch
  • @scaisEdge 是对的。您需要改用 ProjectSearch(如果已经用 Gii 构建),它有一个 Search 方法,该方法返回一个 activeDataProvider 实例。这就是 ActiveQuery 的用途:stackoverflow.com/questions/31948917/…

标签: php yii2


【解决方案1】:

尝试使用

public function actionIndex()
{
    $searchModel  = new ProjectsSearch();

代替

$searchModel  = new ProjectsQuery();

【讨论】:

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