redirect_to(@model) 在 Rails 中是什么意思？答案

【问题标题】：what does redirect_to(@model) means in rails?redirect_to(@model) 在 Rails 中是什么意思？
【发布时间】：2011-08-20 10:07:01
【问题描述】：

从这个 url http://www.helloworlder.com/?p=6 我找到了 redirect_to 或 render 的语法，需要一个字符串。

像这样：

render(:action=>’my_action’)
redirect_to(:action=>’my_action’)

但在 ruby rails 指南中，我看到类似 redirect_to(@model) 的内容。在他们的文档中声明它将显示行动。请解释redirect_to(@model) 是什么意思。

谢谢

【问题讨论】：

标签： ruby-on-rails

【解决方案1】：

例如，您有一个 Post 模型。

redirect_to @model 会带你到这个页面：

http://yourapp/posts/:id/show

【讨论】：

【解决方案2】：

您可以在此处查看源代码： https://github.com/rails/rails/blob/master/actionpack/lib/action_dispatch/routing/polymorphic_routes.rb

redirect_to 接受 Model 时，会通过几个方法过滤，获取调用 polymorphic_url 方法的路径。这个方法[1]的API其实有很多细节，这里抄自cmets：

  # Constructs a call to a named RESTful route for the given record and returns the
  # resulting URL string. For example:
  #
  #   # calls post_url(post)
  #   polymorphic_url(post) # => "http://example.com/posts/1"
  #   polymorphic_url([blog, post]) # => "http://example.com/blogs/1/posts/1"
  #   polymorphic_url([:admin, blog, post]) # => "http://example.com/admin/blogs/1/posts/1"
  #   polymorphic_url([user, :blog, post]) # => "http://example.com/users/1/blog/posts/1"
  #   polymorphic_url(Comment) # => "http://example.com/comments"
  #
  # ==== Options
  #
  # * <tt>:action</tt> - Specifies the action prefix for the named route:
  #   <tt>:new</tt> or <tt>:edit</tt>. Default is no prefix.
  # * <tt>:routing_type</tt> - Allowed values are <tt>:path</tt> or <tt>:url</tt>.
  #   Default is <tt>:url</tt>.
  #
  # ==== Examples
  #
  #   # an Article record
  #   polymorphic_url(record)  # same as article_url(record)
  #
  #   # a Comment record
  #   polymorphic_url(record)  # same as comment_url(record)
  #
  #   # it recognizes new records and maps to the collection
  #   record = Comment.new
  #   polymorphic_url(record)  # same as comments_url()
  #
  #   # the class of a record will also map to the collection
  #   polymorphic_url(Comment) # same as comments_url()

基本上，您的问题的答案是它（等效地）调用模型的 model_path(@model) 方法。

[1]http://apidock.com/rails/ActionController/PolymorphicRoutes/polymorphic_url

【讨论】：