【发布时间】:2018-07-24 15:21:03
【问题描述】:
在以下 C++ 代码中,bar<func_ptr>(); //does not work 行导致编译错误:
#include <iostream>
using namespace std;
void foo(){
cout<<"Hello world";
};
template<void(*func)()>
void bar(){
(*func)();
}
int main() {
using fun_ptr_type= void(*)();
constexpr fun_ptr_type func_ptr=&foo;
bar<&foo>(); //works
bar<func_ptr>(); //does not work
return 0;
}
g++的输出是这样的:
src/main.cpp: In function ‘int main()’:
src/main.cpp:19:16: error: no matching function for call to ‘bar()’
bar<func_ptr>(); //does not work
^
src/main.cpp:10:6: note: candidate: template<void (* func)()> void bar()
void bar(){
^~~
src/main.cpp:10:6: note: template argument deduction/substitution failed:
src/main.cpp:19:16: error: ‘(fun_ptr_type)func_ptr’ is not a valid template argument for ty
pe ‘void (*)()’
bar<func_ptr>(); //does not work
^
src/main.cpp:19:16: error: it must be the address of a function with external linkage
我不明白为什么当我直接将foo 的地址作为模板参数传递时它会起作用,但是当我传递 constexpr func_ptr 时,代码不再编译,即使它恰好包含 @987654328 的地址@ 在编译时。谁能给我解释一下?
编辑:我的 g++ 版本是
$ g++ --version
g++ (Debian 6.3.0-18+deb9u1) 6.3.0 20170516
Copyright (C) 2016 Free Software Foundation, Inc.
This is free software; see the source for copying conditions. There is NO
warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.
【问题讨论】:
标签: c++ templates function-pointers