如何将 4 个数组列表作为 httpurlconnection 的输入传递 Get

Question

我有 4 个列表，这是 mysql 表的输入。如何在 httpurlconnection 中传递这些列表参数以获取 JSON 响应。下面是我的代码。 List1={"1","2"},List2={"50","60"},List3={"Type2","Type4"} 和 List4={"2015"}

             public static final String FetchURL = "http://xxxx.xxxx.com/fetchdesc.php";     
            new fetchDescInBackground().execute(FetchURL);
            URL url = new URL(params[0]);   
            HttpURLConnection connection = (HttpURLConnection) url.openConnection();

            ArrayList<NameValuePair> dataToSend1 = new ArrayList<>(params[0]);
            ArrayList<NameValuePair> dataToSend2 = new ArrayList<>(params[1]);
             ArrayList<NameValuePair> dataToSend3 = new ArrayList<>(params[2]);    
              ArrayList<NameValuePair> dataToSend4 = new ArrayList<>(params[3]);
       InputStream inputStream = connection.getInputStream();
       InputStreamReader inputStreamReader = new InputStreamReader(inputStream);
       BufferedReader bufferedReader = new BufferedReader(inputStreamReader);
       StringBuilder stringBuilder = new StringBuilder(); 
       String tempstring;

              while ((tempstring = bufferedReader.readLine()) != null) {
                  stringBuilder.append(tempstring);
                stringBuilder.append("\n");
                }

如何将 4 列表作为输入传递给 mysql？只有一张表可以为表中的列输入值。请帮忙。

Answer 1

看看这段代码：

URL url = new URL("http://yoururl.com");
HttpsURLConnection conn = (HttpsURLConnection) url.openConnection();
conn.setRequestMethod("GET");


List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("firstParam", paramValue1));
params.add(new BasicNameValuePair("secondParam", paramValue2));
params.add(new BasicNameValuePair("thirdParam", paramValue3));

OutputStream os = conn.getOutputStream();
BufferedWriter writer = new BufferedWriter(
        new OutputStreamWriter(os, "UTF-8"));
writer.write(getQuery(params));
writer.flush();
writer.close();
os.close();

conn.connect();

根据你的输入参数要求使用这个